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eimsori [14]
3 years ago
6

The high school courtesy club bought red and black ink pens for Teacher Appreciation Day. The club bought 75 pens in all. Each b

lack pen cost $1.75, and each red pen cost $2.00. The club spent $137 altogether for the pens. How many black pens did the club buy?
13
23
48
52
Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

52

Step-by-step explanation:


You might be interested in
Order these numbers from least to greatest.
Lorico [155]

Answer:

1. -√19   2. 4.56   3. √21   4. 23/5

Step-by-step explanation:

6 0
3 years ago
Help! Thanks!!!!!!!!!
san4es73 [151]

1)

∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰

AB = 370 m

AC = 510 m

To find BC we can use cosine law.

a² = b² + c² -2bc*cos A

|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)

|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =

|BC| ≈ 553 m


2)

To find ∠ACB, we are going to use law of sine.

sin(∠BAC)/|BC| = sin(∠ACB)/|AB|

sin(76⁰)/553 m = sin(∠ACB)/370 m

sin(∠ACB)=(370*sin(76⁰))/553 =0.6492

∠ACB = 40.48⁰≈ 40⁰


3)

∠BAC = 76⁰

∠ACB = 40⁰

∠CBA = 180-(76+40) = 64⁰


Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰


4)

Shortest distance from A to BC is height (h) from A to BC.


We know that area of the triangle

A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).

Also, area the same triangle

A= (1/2)|BC|*h = (1/2)*553*h.


So, we can write

(1/2)*370*510*sin(76⁰) =(1/2)*553*h

370*510*sin(76⁰) =553*h

h= 370*510*sin(76⁰) / 553= 331 m

h=331 m


4 0
3 years ago
Sharon is conducting research on two species of birds at a bird sanctuary. The number of birds of species A is represented by th
e-lub [12.9K]

Answer: After 7 years the number of birds of species A and B are same. and the number of birds during that year will be 140.


Step-by-step explanation:

Given: Sharon is conducting research on two species of birds at a bird sanctuary.

The number of birds of species A is represented by the equation below,where S represents the number of birds, x years after beginning her research.

S=2^x+12

The number of birds of species B is represented by the equation below,where S represents the number of birds, x years after beginning her research.

S=15x+35

To plot the above function, first find points by which they are passing.

For species A, At x=0 , S=1+12=13

At x=2 , S=2+12=14

Similarly find more points and plot curve on graph.

For species A, At x=0 , S=0+35=35

At x=2 , S=15+35=50

Plot a line with the help of these two points.

Now, from the graph the intersection of curve (for A) and line (for B) is at (7,140) which tells that After 7 years the number of birds of species A and B are same. and the number of birds during that year will be 140.



8 0
3 years ago
Read 2 more answers
Adam had the chicken pox and had to stay inside even though he didn't feel very bad at all. He decided to make a cake to surpris
Elena L [17]
Your answer would be
he needs .4 Liters of milk

Hope this helps :)

3 0
3 years ago
The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.
nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of  average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x).  Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.  

With reference to table we get

\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85

and

b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97


∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31


4 0
3 years ago
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