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eimsori [14]
3 years ago
6

The high school courtesy club bought red and black ink pens for Teacher Appreciation Day. The club bought 75 pens in all. Each b

lack pen cost $1.75, and each red pen cost $2.00. The club spent $137 altogether for the pens. How many black pens did the club buy?
13
23
48
52
Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

52

Step-by-step explanation:


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Consider the inequality-5(x+7)<-10 write an inequality representing the solution for x
GrogVix [38]

Answer:

<h2>x > -5</h2>

Step-by-step explanation:

-5(x + 7) < -10            <em>use the distributive property </em><em>a(b + c) = ab + ac</em>

(-5)(x) + (-5)(7) < -10

-5x - 35 < -10         <em>add 35 to both sides</em>

-5x < 25         <em>change the signs</em>

5x > - 25       <em>divide both sides by 5</em>

x > -5

6 0
2 years ago
To decrease an amount by 4% what single multiplier would u use ??
serg [7]

If you decrease something by 4 percent,

you are  keeping (100% - 4%) or 96% of the original

so multiply by the original amount by 96 percent or .96


If you have 100 pennies, and you  give 4 away ( 4 percent decrease), you still have 96 pennies.  You are keeping 96 percent of what you started with.  This works no matter how much you start with.


Example:


you have 40 dollars

4% decrease

40 * .04 =  1.6 take this away

40 - 1.6 = 38.4 left

you keep 96 percent

40 * .96 = 38.4 left

3 0
3 years ago
Read 2 more answers
Pls help I give brainliest to the best!!!!!!!!!!
Neporo4naja [7]

Answer:

m

2

−2m+3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the points on the lemniscate where the tangent is horizontal. 8(x2 + y2)2 = 81(x2 − y2)
slamgirl [31]
<span>The answers to this problem are:<span>(<span>±5</span></span>√3/8,±5/8)<span>Here is the solution:
Step 1: <span><span><span>x2</span>+<span>y2</span>=<span>2516</span>[2]</span><span><span>x2</span>+<span>y2</span>=<span>2516</span>[2]</span></span>

Step 2: Substitute:<span> 
</span><span><span>8<span><span>(<span>25/16</span>)^</span>2</span>=25(<span>x^2</span>−<span>y^2</span>)
</span><span>8<span><span>(<span>25/16</span>)^</span>2</span>=25(<span>x^2</span>−<span>y^2</span>)</span></span>
</span><span>x^2</span>−<span>y^2</span>=<span>25/32</span><span>.

Add [2] and [3]:<span> 
</span><span>2<span>x^2</span>=<span>75/32
</span><span>x^2</span>=<span>75/74</span></span>
<span>x=±5</span></span>√3/8<span>
Substitute into [2]:<span> 
</span><span><span>75/64</span>+<span>y^2</span>=<span>50/32
</span><span>y^2</span>=<span>25/64</span></span>
<span>y=±<span>5/8</span></span>

</span>
</span>
3 0
3 years ago
Read 2 more answers
A box with a square base and open top must have a volume of 32,000 cm3. find the dimensions of the box that mini- mize the amoun
zmey [24]
Alrighty


squaer base so length=width, nice


v=lwh
but in this case, l=w, so replace l with w
V=w²h

and volume is 32000
32000=w²h


the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW

alrighty

we gots
SA=W²+4HW and
32000=W²H

we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute

SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W

take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?

0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W

so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H

the box is 20cm height and the width and length are 40cm
7 0
3 years ago
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