1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andreev551 [17]
3 years ago
5

THANK YOU FOR ANSWERING

Mathematics
1 answer:
anyanavicka [17]3 years ago
4 0

divide the points by the multiplier 1.9

 so 3.8 /1.9 =2

 the base score was 2.0

You might be interested in
A certain region currently has wind farms capable of generating a total of 2500 megawatts ​(2.5 ​gigawatts) of power. Complete p
marishachu [46]

Answer:

<u>The correct answer is A. 7,665'000,000 kilowatt-hours per year and B. 766,500 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,500 Megawatts or 2.5 Gigawatts

2. Let's resolve the questions a and b:

Part A

Assuming wind farms typically generate 35​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,500 * 0.35 = 875 Megawatts

875 Megawatts = 875 * 1,000 Kilowatts = 875,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

875.000 Kw generated by the farms means that are capable of produce 875,000 kw per hour of energy

875,000 * 24 = 21'000,000 kilowatt-hours per day

<u>21'000,000 * 365 = 7,665'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (7,665'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  7,665'000,000/10,000 = 766,500</u>

4 0
2 years ago
any whole number containing 3 or more digits can be ÷ by 4 if the last two digits form a number that is divisible by 4 why?​
NARA [144]

Answer:

100 is always divisible by 4. Therefore it doesn't matter which number is up front.

the two other digits are important because there are 2-digit-numbers that are not divisible by four. "14" is not divisible by four, but "24" is.

34 isn't divisible, 44 is, 54 isn't.

So both digits will need to form a number that is divisible by 4, or it will not work.

Step-by-step explanation:

n/A

8 0
2 years ago
Which of the following is a unit rate?
Sati [7]

Answer:

the second one

Step-by-step explanation:

Its measuring by miles per hour

5 0
3 years ago
Read 2 more answers
Please help me with this.
Dmitrij [34]

Answer:

the answer is 12

Step-by-step explanation:

4 0
3 years ago
-3 1/3-5 2/3 - (-2 1/3)
Leni [432]

Answer:

-20/3

The exact form is -20/3

The decimal form is -6.6 repeating

The mixed number form is -6 2/3

Hope this helps!

<u><em>PLEASE, </em></u>consider brainliest. I only have 3 left and then my rank will go up.

8 0
3 years ago
Other questions:
  • Which equation below is equivalent to sin C=h/a ?
    6·1 answer
  • Help please...........
    8·2 answers
  • Match the following pair of angles with their respective definitions.HELP
    10·2 answers
  • Arlington and Vernonville are 160 miles apart. A car leaves Arlington traveling towards​ Vernonville, and another car leaves Ver
    8·2 answers
  • Molly bought 12.5 yards to make dog beds. She uses 2.5 yards of fabric for each dog bed. She sells each dog bed for 17.50. After
    8·2 answers
  • August 22 3months later what day would it be
    7·1 answer
  • Help please thank you
    9·2 answers
  • Jill swam 200 meters in 2 minutes 42 seconds. If each lap is 50 meters long, which time is her estimated time, in seconds, per l
    9·2 answers
  • Identify the type of function represented by f(x)= 3/8(4)^x
    12·1 answer
  • Identify the zero(s) of the function graphed below
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!