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viva [34]
3 years ago
10

A certain region currently has wind farms capable of generating a total of 2500 megawatts ​(2.5 ​gigawatts) of power. Complete p

arts​ (a) and​ (b) below
a. Assuming wind farms typically generate 35​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year? Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?
Mathematics
1 answer:
marishachu [46]3 years ago
4 0

Answer:

<u>The correct answer is A. 7,665'000,000 kilowatt-hours per year and B. 766,500 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,500 Megawatts or 2.5 Gigawatts

2. Let's resolve the questions a and b:

Part A

Assuming wind farms typically generate 35​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,500 * 0.35 = 875 Megawatts

875 Megawatts = 875 * 1,000 Kilowatts = 875,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

875.000 Kw generated by the farms means that are capable of produce 875,000 kw per hour of energy

875,000 * 24 = 21'000,000 kilowatt-hours per day

<u>21'000,000 * 365 = 7,665'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (7,665'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  7,665'000,000/10,000 = 766,500</u>

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Step-by-step explanation:

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Mean is given by:

(1950+1952+ 1908+1902+1955+1954+1901+1910)/8

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absolute deviation from mean is:

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1902+1908)/2

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Mean is given by:

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