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2 years ago

Is anyone willing to help me

Mathematics

2 answers:

ehidna [41]2 years ago

5 0

Answer:

5.8, and 6.3

Step-by-step explanation:

the numbers are going up by ".5"

eimsori [14]2 years ago

4 0

Answer:

5.8 and 6.3 because you can see the pattern.

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Please helppp (had to have 20 words haha)

s2008m [1.1K]

Answer:

w==77

Step-by-step explanation:

The sum of the 2 opposite interior angles equals the exterior angle.

w-36 +w-20=w+21

combine like terms: 2w-56=w+21

subtract w from both sides: w-56=21

add 56 to both sides: <u>w=77</u>

6 0

3 years ago

What is the effect on the graph of f(x) = 1 when it is transformed to

ivann1987 [24]

Answer: C) Shifted 16 units down

The minus 16 at the end is directly the reason why. Think of y = 1/x, and subtracting 16 from both sides to get y-16 = (1/x) - 16. The y-16 will shift every point down 16 units. For instance, the point (1, 1) moves to (1, -15).

5 0

3 years ago

Read 2 more answers

(08.01)Consider the following system of equations:

Anika [276]

Lines y = −2x + 3 and y = 3x – 5 intersect the x-axis.

5 0

2 years ago

Help please just answer would be fine

scZoUnD [109]

The amount of water decreases $16\frac{1}{2}$ pints in 12 weeks.

Solution:

The amount of water decreases in 7 weeks = $9\frac{5}{8}$ pints

The amount of water decreases each week is same.

Let us first change the mixed fraction into improper fraction.

$9\frac{5}{8}$ pints = $\frac{(9\times8)+5}{8}$

$=\frac{77}{8}$ pints

The amount of water decreases in 1 week

$$=\frac{\frac{77}{8} }{7}$

$=\frac{77}{8\times7}$

$=\frac{11}{8}$

So, the amount of water decreases in 1 week is $\frac{11}{8}$ pints.

The amount of water decreases in 12 week

$=\frac{11}{8}\times12$

$=\frac{132}{8}$

$=16\frac{4}{8}$

$=16\frac{1}{2}$ pints

Hence the amount of water decreases $16\frac{1}{2}$ pints in 12 weeks.

4 0

3 years ago

How do I solve this out??

GuDViN [60]

<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

$\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]$

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

$\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]$

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0

2 years ago