3 years ago

How to solve this equation x2-5x=0

Mathematics

1 answer:

vodka [1.7K]3 years ago

5 0

Answer:

x = 5

Step-by-step explanation:

x² - 5x = 0

(x² - 5x) /x = 0/x

x²/x - 5x/x = 0

x - 5 = 0

x = 5

Check:

x² - 5x = 0

5² - 5*5 = 0

25 - 25 = 0

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In the figure, PQ is parallel to RS. The length of RP is 5cm; the length of PT is 30cm; the length of QT is 60cm. What is the le

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The triangles PTQ and RTS are similar; so the ratios of corresponding sides are equal.

Let us denote the unknown length SQ as x.

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$\begin{gathered} \frac{30}{30+5}=\frac{60}{60+x} \\ \end{gathered}$

Cross multiply to obtain;

$\begin{gathered} 30(60+x)=60(35) \\ 1800+30x=2100 \\ \text{collect like terms} \\ 30x=2100-1800 \\ 30x=300 \\ \text{divide both sides by 30} \\ \frac{30x}{30}=\frac{300}{30} \end{gathered}$

Therefore;