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3 years ago

8

An equation using three variables is graphed in coordinate space

1 answer:

balandron [24]3 years ago

6 0

This is not possible. False.

(BLASPHEMY I SAY!)

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20 is 25% of what number

borishaifa [10]

Hey there! :D

If 20 is 25% of a number,

we know that it is a quarter of a number.

20*4= 80

20 is 25% of 80.

I hope this helps!
~kaikers

5 0

4 years ago

Read 2 more answers

Solve the inequality.

svetlana [45]

Answer:

Step-by-step explanation:

n ≥ -2 + 9

n ≥ 7

3 0

3 years ago

Read 2 more answers

Graph the two lines 2x + 3y = 18 , 3x -4y > 16.

Dmitrij [34]

The domain and range for each line is all real numbers. This is because all numbers are possible to input into x and all y values exist.

The slope of the first line is -2/3 and the y intercept is 6. You can reach this conclusion by solving for y (putting it in slope intercept form).

The slope of the second one is 3/4. and the y intercept is all real numbers greater than -4. This is true because it is an inequality and you can find these numbers by solving for y.

7 0

3 years ago

Pls help i will mark brainlyest

Sergeeva-Olga [200]

Answer:

∠b=82°

Step-by-step explanation:

143°=∠c+∠b (exterior angle property)

143°=61°+∠b

∠b=143-61

∠b=82°

4 0

3 years ago

(1.)Find the slope of the line that passes through the given pair of points. (If an answer is undefined, enter UNDEFINED.) (?a +

jekas [21]

Answer:

1. The slope of the line is $m=\frac{-2b+3}{2a}$ .

2. The value of a is 18.

Step-by-step explanation:

If a line passes through two points, then the slope of the line is

$m=\frac{y_2-y_1}{x_2-x_1}$

(1)

It is given that the line passes through the points (-a + 3, b - 3) and (a + 3, -b). So, the slope of the line is

$m=\frac{-b-(b-3)}{a+3-(-a+3)}$

$m=\frac{-b-b+3}{a+3+a-3)}$

$m=\frac{-2b+3}{2a}$

The slope of the line is $m=\frac{-2b+3}{2a}$ .

(2)

If the line passing through the points (a, 1) and (6, 5), then the slope of the line is

$m_1=\frac{5-1}{6-a}=\frac{4}{6-a}$

If the line passing through the points (2, 7) and (a + 2, 1), then the slope of the line is

$m_2=\frac{1-7}{a+2-2}=\frac{-6}{a}$

The slopes of two parallel lines are same.

$m_1=m_2$

$\frac{4}{6-a}=\frac{-6}{a}$

On cross multiplication we get

$4a=-6(6-a)$

$4a=-36+6a$

$4a-6a=-36$

$-2a=-36$

Divide both sides by -2.

$a=18$

Therefore the value of a is 18.

8 0

3 years ago