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mel-nik [20]
3 years ago
5

(x + 3)2 + (y – 5)2 = 1 What would be the center of this?

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
8 0

Answer:

(- 3, 5 )

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 3)² + (y - 5)² = 1 ← in standard form

with centre = (h, k) = (- 3, 5 )

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swat32
One way is to estimate
1^2=1
2^2=4
3^2=9
4^2=16
5^2=25
6^2=36
7^2=49
8^2=64
the number 61 is between 49 and 64 therefor the square root of 61is between the intigers 7 and 8 or -7 and -8
8 0
3 years ago
Find the value of x.
Genrish500 [490]

Answer:

11

Step-by-step explanation:

All angles on a triangle equal 180. 80+60=140.

Now to solve for x, we set it to equal 40 for 180-140.

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3 years ago
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What is the axis of symmetry of a parabola if its x-intercepts are -3 and 5?
ollegr [7]

Answer:

The axis of symmetry will be at 1

Step-by-step explanation:

The middle of -3 and 5 will be the axis :)

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1

3 0
4 years ago
1/2×1/3×1/4 need to show work
klasskru [66]
1x1x1=1
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3 0
4 years ago
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The radius of one circle is three the time radius of another circle. The sum of their areas is 12pi. Find the radius of each cir
zlopas [31]
   
\displaystyle\\
\begin{cases}
R_1 = 3R_2\\
\pi R_1^2 +\pi R_2^2=12\pi ~~~\Big|~~:\pi 
\end{cases} \\  \\ 
\begin{cases} 
R_1 = 3R_2\\
R_1^2 + R_2^2=12 
\end{cases} \\  \\ 
(3R_2)^2+ R_2^2=12 \\  \\ 
9R_2^2 + R_2^2=12 \\  \\ 
10R_2^2=12\\\\
R_2^2 = \frac{12}{10} = \frac{6}{5}  \\  \\ 
R_2 =  \boxed{\sqrt{\frac{6}{5}} } \\  \\ 
R_1 = \boxed{3\sqrt{\frac{6}{5}} }



7 0
3 years ago
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