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denis23 [38]
3 years ago
6

on Monday camila spent 4 2/6 hours studying on Tuesday spent another 3 5/6 hours studying what is the combined length of the tim

e she spent studying
Mathematics
1 answer:
erastova [34]3 years ago
5 0

She spent 8 1/6 hours studying

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olganol [36]
0 because the answer is 0.67
4 0
3 years ago
Explain in words,how to find the product of -4(-1.5) using a number line. Where do you end up?
Gemiola [76]

Answer:

so u multiply negative four times nagative 1.5

6 0
3 years ago
Find the value of x in the triangle. Please show work. Help
Assoli18 [71]

there is no triangle drawn

4 0
3 years ago
In a given right triangle, If 0 º < x < 90 º and cos x = √ 3 / 2, then sin x = ?
nordsb [41]

Answer:

  1/2

Step-by-step explanation:

The "Pythagorean relation" between trig functions can be used to find the sine.

<h3>Pythagorean relation</h3>

The relation between sine and cosine is the identity ...

  sin(x)² +cos(x)² = 1

This can be solved for sin(x) in terms of cos(x):

  sin(x) = √(1 -cos(x)²)

<h3>Application</h3>

For the present case, using the given cosine value, we find ...

  sin(x) = √(1 -(√3/2)²) = √(1 -3/4) = √(1/4)

  sin(x) = 1/2

__

<em>Additional comment</em>

The sine and cosine of an angle are the y and x coordinates (respectively) of the corresponding point on the unit circle. The right triangle with these legs will satisfy the Pythagorean theorem with ...

  sin(x)² + cos(x)² = 1 . . . . . . where 1 is the hypotenuse (radius of unit circle)

A calculator can always be used to verify the result.

6 0
1 year ago
HELP IVE BEEN STRUGGLING FOR THE PAST 15 MIN PLEASEEEEE
joja [24]

<u>Answer:</u>

c=  -1/2

<u>Step-by-step explanation:</u>

Let's solve your equation step-by-step.

4 /3  = −6c − 5/ 3

Step 1: Simplify both sides of the equation.

4 /3  =−6c +  −5 /3

Step 2: Flip the equation.

−6c +  −5 /3  =  4/3

Step 3: Add 5/3 to both sides.

−6c +  −5 /3  +  5 /3  = 4/3  +  5 /3  −6c

=3

Step 4: Divide both sides by -6.

−6c  −6   =  3 − 6 c =  −1 /2

4 0
3 years ago
Read 2 more answers
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