on Monday camila spent 4 2/6 hours studying on Tuesday spent another 3 5/6 hours studying what is the combined length of the tim
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- A marker in the center of the fairway is 150 yards away from the centre of the green
- While standing on the marker and facing the green, the golfer turns 100° towards his ball
- Then he peces off 30 yards to his ball
- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>
Let assume that the distance between the golf ball and central of green is x
<u>Here</u><u>, </u>
- Distance between marker and centre of green is 150 yards
- <u>That </u><u>is</u><u>, </u>Height = 150 yards
- For facing the green , The golfer turns 100° towards his ball
- <u>That </u><u>is</u><u>, </u>Angle = 100°
- The golfer peces off 30 yards to his ball
- <u>That </u><u>is</u><u>, </u>Base = 30 yards
<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>
- Here, a = perpendicular height
- b = base
- c = hypotenuse
- cos theta = Angle of cosine
<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>
<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>
Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards
<h3>Answer: Check out the diagram below.</h3>
Explanation:
Use your straightedge to extend segment AB into ray AB. This means you'll have it start at A and go on forever through B. Repeat these steps to turn segment AC into ray AC.
The two rays join at the vertex angle A. Point A is the center of the universe so to speak because it's the center of dilation. We consider it an invariant point that doesn't move. Everything else will move. In this case, everything will move twice as much compared to as before.
Use your compass to measure the width of AB. We don't need the actual number. We just need the compass to be as wide from A to B. Keep your compass at this width and move the non-pencil part to point B. Then mark a small arc along ray AB. What we've just done is constructed a congruent copy of segment AB. In other words, we've just double AB into AB'. This means the arc marking places point B' as the diagram indicates.
The same set of steps will have us construct point C' as well. AC doubles to AC'
Once we determine the locations of B' and C', we can then form triangle A'B'C' which is an enlarged copy of triangle ABC. Each side of the larger triangle has side lengths twice as long.
Note: Points A and A' occupy the same exact location. As mentioned earlier, point A doesn't move.
