From the information given about the square pyramid, the maximum base length of the building is 67.42 cm.
<h3>How do you determine the maximum side length?</h3>
We are given the following details are:
Base = b
Slant height (l) = 5b
The lateral surface area is calculated using:
L = 2bl
So, we have:
L = 2 * b * 5b
Evaluate the product
L = 10b²
The total surface area is calculated using:
T = L + b²
So, we have:
T = 10b² + b²
Evaluate the sum
T = 11b²
Recall that the maximum surface area is 50,000 square feet
So, we have:
11b² = 50000
Divide both sides by 11
b² = 50000/11
Taking the square root of both sides, we have
b = 67.42
Hence, the maximum base length of the building is 67.42 cm
Learn more about square pyramids at:
brainly.com/question/12146629
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Answer:
B. 0
Step-by-step explanation:
=>d+(-d)
=>d-d
=>0
You subtrscy the bigger number (2010's population) by the smaller one (1910's population). 237194-608660= 371,466.
When you round to the 100's you check the 10's place. If 5 or higher add a 1 to the hundreds place, and make the 1's and 10's place 0. If lower don't add anything and make the 1's and 10's place into 0s.
When you round it, you will get 371,400
we are given that
angle(ACF)=90
angle(ACB)=61
sum of all angles along any line is 180
so, we get
angle(ACF)+angle(ACD)=180
we can plug value
90+angle(ACD)=180
angle(ACD)=90
now, we can use formula
angle(ACD)=angle(ACB)+angle(BCD)
now, we can plug values
and we get
90=61+angle(BCD)
90-61=61-61+angle(BCD)
angle(BCD)=29................Answer
Answer:
cos q = 3/5
Step-by-step explanation:
Standard position means the vertex (point or corner of the angle) is at (0,0) and one side of the angle is glued to the positive x-axis (facts, but not technical math terms) See image. Special triangles have all three sides nice and clean with whole number lengths, we call these Pythagorean triples. 3-4-5 is your most basic Pythagorean triple. So we don't even have to calculate the hypotenuse, see image. Now the triangle shown is easy to work with, using entry-level trig...cos = ADJ/HYP. So we get 3/5=.6 BUUuuuut, the angle q in the original problem is actually the giant angle, marked in yellow (see image) and we're in the fourth quadrant which means there's negative numbers all over the place. So just to be sure the answer is .6 and not -.6 Check your signs. One trick to remember is the ASTC markings in the quadrants. I use All Students Take Calculus, but what it means is in the first quadrant All the trig functions are positive. Only Sine (and fam) are positive in the 2nd quadrant. Tan (and fam) in the 3rd and Cos and fam in the 4th quadrant. It's a good quick check.
cos q = 3/5 OR cos q = .6
