Answer:
The parallelogram is not rectangle because the sides of the parallelogram do not meet at right angles.
Step-by-step explanation:
Given the parallelogram with sides 20 and 21 units with diagonal length 28 units.
we have to tell it is a rectangle or not.
The given parallelogram is rectangle if the angle at vertices are of 90° i.e the two triangle formed must be right angles i.e it must satisfy Pythagoras theorem
=
+
784=400+441=881
Not verified
∴ The sides of the parallelogram do not meet at right angles.
Hence, the parallelogram is not rectangle because the sides of the parallelogram do not meet at right angles.
Hope it helps
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Here, I've attached a picture of the triangle that accompanies this explanation.
cot = = =
Now view the triangle.
PS. Angle theta will have a coordinate of (-, +) because it is in quadrant II.
sin of the angle would be opposite/hypotenuse, so sin =
cos of the angle would be adjacent/hypotenuse, so cos =
tan of the angle would be opposite/adjacent, so tan =
B if you need an explanation just comment
Answer:
Solution: (-1, -1)
Step-by-step explanation:
y=4x+2
y=-4/3x-2
Solve by graphing.
First, you need to plot the y-intercept.
y=4x+<u>2</u>
2 will be your y-intercept.
Next, you plot your slope.
y=<u>4x</u>+2
From your y-intercept, you will go up 4 and right one space, if you run out of space go down 4 and left 1.
Now repeat the same steps for the next one.
y=-4/3x<u>-2</u>
Plot your y-intercept.
y=<u>-4/3x</u>-2
because your slope is negative you will go down 4 and right 3, if you run out of room go up 4 and left 3.
Then draw connecting lines and wherever the lines intersect, that's going to be your solution. In this case, the solution is (-1, -1).
Hope this helps :)