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2 years ago

Write an equation that is perpendicular to x-3y=2 and contains the point (2,4)

Mathematics

1 answer:

Kisachek [45]2 years ago

6 0

perp to x-3y=2 thru (2,4)

For perpendicular we swap the coefficients on x and y, negating one

3x + y = some constant

We get the constant in the obvious way from the point

3x + y = 3(2) + 4 = 6 + 4 = 10

Answer: 3x + y = 10

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Using n for the variable, write an algebraic expression that represents a number that is divisible by the given number. (Hint: A

iris [78.8K]

Answer:

'5n' is the correct answer.

Step-by-step explanation:

Let 'n' be any integer i.e. a number from the set {....., -3,-2,-1,0,1,2,3, ..... }

so 'n' can be termed as the variable here because its value can change and can be any value from the above set.

A number 'q' that can be divided by a a given number 'p' can be written as:

$n \times p$

When divided by 'p' :

$\dfrac{q}p = \dfrac{n \times p}{p}\\\dfrac{q}p = n$

So, The number 'q' is completely divisible by 'p' leaving 'n' as the quotient.

Using this concept, let us solve the questions:

a) Using 'n' as the variable, a number that is divisible by 5 can be written as:

$5n$

Read more on Brainly.com - brainly.com/question/16919676#readmore

7 0

3 years ago

Solving proportion 10\8=n\10

Zanzabum

$\frac { 10 }{ 8 } =\frac { n }{ 10 } \\ \\ 10\cdot \frac { 10 }{ 8 } =\frac { n }{ 10 } \cdot 10\\ \\ \frac { 100 }{ 8 } =n$

$\\ \\ n=\frac { 4\cdot 25 }{ 4\cdot 2 } \\ \\ \therefore \quad n=\frac { 25 }{ 2 }$

6 0

2 years ago

Read 2 more answers

The points represented by the (x, y) coordinate pairs in the

77julia77 [94]

Step-by-step explanation:

For every increase in the x-value by 1,

the y-value decreases by -2.

(From 3 to 1 and from 1 to -1)

Hence, slope of line k

= Rise/Run = (-2)/1 = -2. (A)

5 0

2 years ago

(5in.)(8 in.) <br>-------------- <br> 2

DerKrebs [107]

Answer:

Step-by-step explanation:

(8 * 5) / 2

=> 40/2

=> 20

6 0

3 years ago

Which is the graph of the function f(x) = x2 + 2x + 3?

blagie [28]

Dy/dx=2x+2

So velocity will be zero when 2x+2=0, x=-1

Since d2y/dx2=2, it has a constant positive acceleration of 2, so that when dy/dx=0 it is at an absolute minimum value for f(x), which is also the vertex.

y(-1)=1-2+3=2

So the vertex is at (-1,2), which is an absolute minimum so the parabola opens upwards.

And by symmetry we can say that f(0)=f(-2)=3 so you have another two points that you can see (-2,3) and (0,3)

5 0

3 years ago

Read 2 more answers