Using derivatives, it is found that:
i) 
ii) 9 m/s.
iii) 
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:

item i:
Velocity is the <u>derivative of the position</u>, hence:

Item ii:

The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:

Item iv:

The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:




Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
Answer:
1.3
Step-by-step explanation:
The two points lie on the same vertical line (x=2), so the distance between them is the difference of their y-coordinates:
2.5 - 1.2 = 1.3 . . . distance between the points
This equation is currently in Point Slope Form. You can easily convert this form to Y Slope Intercept by following these steps.
Add 3 to both sides.
y = -2(x-2)
Simplify.
y = -2x + 4
Answer: 70 square units
Step-by-step explanation:
Area of kite = (one diagonal * another diagonal) / 2
10 * 14 = 140
140 / 2 = 70