The value of x is 24 because 24-12=12
I worked it out by doing the opposite so by doing 12+12
Then the value of y is also 24 and I used the same method
Answer:
Bad quality and u should´ve payed attention in class
Step-by-step explanation:
....
x - y = 12 ⇒ 3x - 3y = 36
2x + 3y = 76 ⇒ 2x + 3y = 76
5x = 112
5 5
x = 22.4
x - y = 12
22.4 - y = 12
- 22.4 - 22.4
-y = -10.4
-1 -1
y = 10.4
(x, y) = (22.4, 10.4)
Answer:
D,
Step-by-step explanation:
<em>R(x)</em> is a polynomial of degree 7, so it has up to 7 distinct complex roots <em>r</em>₁, ..., <em>r</em>₇, and we can write it in terms of these roots as
<em>R(x)</em> = (<em>x</em> - <em>r</em>₁) (<em>x</em> - <em>r</em>₂) ... (<em>x</em> - <em>r</em>₇)
The coefficients of <em>R(x)</em> are all real, so the roots must all be complex numbers, and any of these roots with non-zero imaginary parts must occur along with their complex conjugates. This means if <em>a</em> + <em>b</em> <em>i</em> is a root, then is <em>a</em> - <em>b</em> <em>i</em> is also a root.
(a) We're told that -5 - 3<em>i</em> and 2<em>i</em> are roots to <em>R(x)</em>, so we also know that -5 + 3<em>i</em> and -2<em>i</em> are roots.
There are 4 roots accounted for, leaving us with 3 unknown roots. These roots cannot all be non-real, because we can only count 2 of them as a conjugate pair. So we can have either
(b) at most 3 real roots, or
(c) at most 2 non-real roots and 1 real root.