The number -33 divisors are:
D(-33) = {-33, -11, -3, -1, 1, 3, 11, 33}
a × b = -33
<u>1) -33 × 1 = -33 ⇒ Sum is: -33 + 1 = -32</u>
2) -11 × 3 = -33 ⇒ Sum is: -11 + 3 = -8
3) -3 × 11 = -33 ⇒ Sum is: -3 + 11 = 8
4) -1 × 33 = -33 ⇒ Sum is: -1 + 33 = 32
<u>5) 1 × (-33) = -33 ⇒ Sum is: 1 + (-33) = 1 - 33 = -32</u>
6) 3 × (-11) = -33 ⇒ Sum is: 3 + (-11) = 3 - 11 = -8
7) 11 × (-3) = -33 ⇒ Sum is: 11 + (-3) = 11 - 3 = 8
8) 33 × (-1) = -33 ⇒ Sum is: 33 + (-1) = 33 - 1 = 32
<h2>The least possible sum of a and b is -32</h2>
to 1) and to 5)
Answer: -60 > -160
Roberto has the higher final score.
Step-by-step explanation:
Hi, to answer this question we have to analyze the information given:
-60 is greater than -160, because -60 is father to the right than -160 on the number line (see attachment)
Since the direction of < and > always points towards the smallest number.
-60 > -160
Roberto has the higher final score.
Feel free to ask for more if needed or if you did not understand something.
The "new" square must have sides of size 8
8 * 8 = 64
so the original square must have had sides of size 5cm. 8 - 3
Answer:
htx
Step-by-step explanation:
(y+5)^2 + (x-1)^2 = 16
[^2 meaning squared]
