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Drupady [299]
3 years ago
6

What is the the value of 3 in 6,300 times the value of 3 in 530?

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
8 0
6300:
The 3 is in the hundreds place, so the value is 3*100=300

530:
The 3 is in the tens place, so the value is 3*10=30

Multiply the values
300*30= 9,000

Final answer: 9,000
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Find the value of each expression.<br> -5 -9 -13
Andrei [34K]

Answer:

-27

Step-by-step explanation:

-5-9=-14

-14-13=-27

3 0
3 years ago
When four times a number n is decreased by 3 it’s at most 21
pashok25 [27]
The number is = 6
……………………………….
8 0
3 years ago
Lisa purchased almonds for $3.00 per pound and she spent $24.90. How many pounds of almonds did she purchase? The price went up
aleksandr82 [10.1K]

Answer:

1. Lisa purchased almonds for $3.00 and spent $24.90.

The quantity of almonds bought is therefore:

= Total amount spent / Cost per pound

= 24.90 / 3

= 8.3 pounds

2. If the price goes up to $3.50 per pound and the maximum Lisa can spend is $25, the number of pounds she can get is:

= Maximum amount for almonds / Price per almonds

= 25 / 3.5

= 7.14 pounds

5 0
3 years ago
Which option lists am expression that is not equivalent to 4^2/3
Vesnalui [34]

remember that

x^{\frac{a}{b}}=\sqrt[b]{x^a}

also x^{-a}=\frac{1}{x^a}

and (a^b)^c=a^{bc}


so

4^{\frac{2}{3}}


first one, that one is clearly not equal since 0.25≠4

2nd one, 0.25=1/4, so 0.25^{\frac{-2}{3}}=(\frac{1}{4})^{\frac{-2}{3}=  \frac{1}{(\frac{1}{4})^{\frac{2}{3}}}=4^{\frac{2}{3}}, which matches

3rd one, \sqrt[3]{16}=\sqrt[3]{4^2}=4^{\frac{3}{2}}, which matches

4th one (\sqrt[3]{4})^2=(4^{\frac{1}{3}})^2=4^{\frac{2}{3}} which matches


answer is 0.25^{\frac{2}{3}}

4 0
3 years ago
Which is an x-intercept of the continuous function in the
Paladinen [302]

Answer:

(-1, 0), (2, 0), (3, 0)

Step-by-step explanation:

x-intercept of a line is defined by a point where y = 0.

So the point in the form of (x, 0) will be the x-intercept of the given continuous function.

From the table attached,

For x = -1, f(-1) = 0

For x = 2, f(2) = 0

For x = 3, f(3) = 0

Points (-1, 0), (2, 0) and (3, 0) are the x-intercepts of the continuous function f(x).

5 0
3 years ago
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