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Lynna [10]
3 years ago
7

Derrick drove 15 miles at an average rate of 30 miles per hour.

Mathematics
1 answer:
leonid [27]3 years ago
4 0
67 miles lololololol
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Which best describes the relationship between the two triangles below?
Nostrana [21]

Answer:

They are SIMILAR triangles

Step-by-step explanation:

Given triangles MNL and FHG with two of their angles to be 51° and 36° respectively. Their third angle is expressed as:

180°-(51°+36°)

= 180°-87°

= 93°

Their third angle is 93°

Since both triangles have the same angles in them, both triangles are considered as similar triangle even though the value of their sides are different due to angle differences in both.

Note that individual triangles are scalene triangles since their angles are not the same but the both triangles are similar triangles based on their relationship.

3 0
4 years ago
Numero mixto de 16 -- 5
stealth61 [152]

Answer:

La respuesta correcta es 3 1/5

Step-by-step explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

3 0
3 years ago
Suppose x represents an objects weight on Earth. Write two expressions: one that you can use to find the objects weight on Mars
tatyana61 [14]
The weight of an object is the product of its mass and the acceleration of gravity.
If g[e] is the acceleration of gravity on earth, and g[M] the same for Mars and g[m] the same for the moon,
then m[M]=m[e]g[M]/g[e] and m[m]=m[e]g[m]/g[e] where m[ ] denotes mass. Note that weight=mg (measured in newtons) while mass is in kilograms.
If g[M]=g[e]/3 and g[m]=g[e]/6 approximately. Then the weight of an object on Mars will be about a third of what it is on earth, while on the moon it would be about a sixth of what it is on earth.
4 0
3 years ago
Need help! will award brainiest
coldgirl [10]

Answer:

\sf slope: \boxed{\bf \frac{1}{3} }

Explanation:

\sf slope :\dfrac{y_2-y_1}{x_2-x_1} =\dfrac{rise}{run} \  \ \  \  where  \ (x_1, \ y_1) ,(x_2, \ y_2)  \ are \ points

Find slope:

\rightarrow \sf \dfrac{x_2-x_1}{y_2-y_1}

<em>insert values</em>

\rightarrow \sf \dfrac{3-5}{-4-2}

<em>simplify</em>

\rightarrow \sf \dfrac{1}{3}

4 0
2 years ago
Read 2 more answers
Parking at a university has become a problem. University administrators are interested in determining the average time it takes
Vikentia [17]

Answer:

<h2>In this particular case,the target population of interest to the university administration constitutes the university students.</h2>

Step-by-step explanation:

  • The university administration is interested to conduct a statistical study to identify the average or mean time taken by the students to find a vacant parking spot.
  • Therefore,the research topic here is the average time taken by the university students to find parking spot. The administrator collects an inconspicuous sample of 240 samples from the target population of the study,which is the overall student population of the university.
  • The sample collected by the university administration is used to observe the average or mean parking time by the university students.
6 0
3 years ago
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