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Lemur [1.5K]
4 years ago
10

What is 1 and 3/4 as an improper fraction

Mathematics
1 answer:
EastWind [94]4 years ago
7 0

\huge\boxed{\frac{7}{4}}

First, turn 1 into an improper fraction with a denominator of 4, which matches \frac{3}{4}.

\displaystyle 1 \frac{3}{4} = \frac{4}{4} + \frac{3}{4}

Now, just add the numerators.

\displaystyle \frac{4}{4} + \frac{3}{4} = \boxed{\frac{7}{4}}

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What's 3/4 times 168
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The correct answer is 126
6 0
3 years ago
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What is the volume of a rectangular prism with a length of 8 1/2 cm, width of 9 1/3 cm and a height of 12 2/5 cm?
Alecsey [184]
8.50 * 9.333333 * 12.40
answer is 983 (11/15)

4 0
4 years ago
Factor completely 56a2b3 − 35ab.
VMariaS [17]

I would start off by taking away 1a. That would make the problem be 56ab3-35b.I only took away 1 because each have at least 1a and is okay to do.


Next I would deal with the variable b. I would cross of 1 b. That's because both sides have at least 1b.  Now, it's shortened to be 56ab2-35.


Since you cannot take away anymore variables, you have to deal with 56 and 35. I start small with dividing each by 2. I am trying to see what the greatest number could be while making the numbers still be whole. That turns 56 into 28 when it's cut in half. The 35 now turns into 17.5.


I would assume your teacher would want the numbers to be whole. seeing as though when 35 is cut in half and makes a decimal number, I would leave them. What I mean by that is to leave the numbers as 56 and 35.


So, that means the answer is 56ab2-35.


I hope this helps!! (And makes sense)

5 0
4 years ago
(d) estimate p(x < 1.5), i.e., the proportion of all thickness values less than 1.5. [hint: if you knew the values of μ and σ
Elan Coil [88]
<span>This question's solution is based on two context. First off, the probability of any events or occurrence cannot be greater than 1. If the question demands finding the probability that the proportion of all thickness (X) is less than 1.5 given the available data (mu and rho) then that would practically be impossible. It would only be feasible to ask, "if it were less than 1" My point is, suppose X is 1.3 which is actually less than 1.5, then we have a contradiction because our probability of occurrence or non-occurrence cannot be greater than 1.On the other hand suppose X is 0.2, then it will be pretty easy to input the formula to get valuable results.</span>
3 0
3 years ago
Holly has $462 in her bank account and takes out $15 each week but does not put any back in. Write an equation/expression to rep
Degger [83]

Answer:

Therefore required expression is

y =462 - t×15

where y represents the amount of money in her bank account in dollar after t week.

Step-by-step explanation:

Given that,

Holly has $462 in her bank account and takes out $15 each week but does not put any back in.

She takes out $15 on first week.

The remaining amount of her bank account is =$(462-15)

                                                                            =$(462 - 1×15)

If she withdraws $15 on second week.

The remaining amount of her bank account is =$(462-15-15)

                                                                            =$(462 - 2×15)

Similarly after third the amount in her account is =$(462 - 3×15)

From the above it is cleared that

The amount in her account after t week is

=$(462 - t×15)

Therefore required expression is

y =462 - t×15

where y represents the amount of money in her bank account in dollar after t week.

3 0
3 years ago
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