1.) Problem: Diff. Shape of the moon
<span>Hypothisis: earth, sun, n moon locations creates a shadow </span>
<span>Experiment: her experiment </span>
<span>Observation: Researching </span>
<span>Conclusion: she is yet to make one </span>
<span>2.) Size of balls - make them accurate </span>
<span>Research: use multiple sources </span>
<span>The amount of light: keep using the same light</span>
Science method. like the gemdas is math there’s a process for science which depends on chem or bio.
Yes, it is possible.
In this case both of the parental plants were heterozygotes and they manifested dominant allele in their phenotype, which is round seed.
P: Aa x Aa
F5: AA, Aa, aA, aa - possible genotypes in fifth generations.
A- dominant allele (round seeds); a- recessive allele (wrinkled seeds)
Wrinkled phenotype is manifested only if there are two recessive alleles present.
Answer:
F1 Females - all wild type
F1 Males - all wild type
F2 Females - - all wild type
F2 Males - 1/2 wild type, 1/2 vermilion
Explanation:
The wild-type allele (Xᵛ⁺) is dominant over vermilion (Xᵛ), which is a sex-linked trait.
Female flies have two X chromosomes, male flies have one X and one Y chromosome.
A homozygous wild-type female fly (Xᵛ⁺Xᵛ⁺) is mated with a vermilion male fly (XᵛY).
The female parent can only produce Xᵛ⁺ gametes.
The male parent can produce either Xᵛ or Y gametes.
When gametes from both parents fuse, the F1 offspring will have the genotypes Xᵛ⁺Xᵛ (females with wild type eyes) and Xᵛ⁺Y (males with wild type eyes).
The F1 females can produce Xᵛ⁺ and Xᵛ gametes. The F1 males can produce Xᵛ⁺ and Y gametes.
When the F1 individuals interbreed, the gametes combine to give rise to the F2 offspring. The possible combination of gametes that will give the different genotypes and phenotypes in the F2 are:
- Xᵛ⁺Xᵛ⁺ females with wild type eyes
- Xᵛ⁺ Y males with wild type eyes
- Xᵛ Xᵛ⁺ females with wild type eyes
- Xᵛ Y males with vermilion eyes
I'm pretty sure it is refraction <span />
