26 skate and with wunno when ask what about the gc and the park to park in
Total pressure is constant and PT = P = 1/2*ρ*v^2
So p1 + 1/2*ρ*v1^2 = p2 + 1/2*ρ*v2^2 and from continuity we have ρ*A1*v1 = ρ*A2*v2
So v2 = v1*A1/A2 since r2 = 2r1 then A2 = 4A1
so v2 = v1/4
Now from above p2 = p1 + 1/2*ρ*v1^2 - 1/2*ρ*v2^2 = p1 + 1/2*ρ*v1^2 - 1/2*ρ*v1^2/4^2
So p2 = 3.0x10^4Pa + 1/2*1000kg/m^3*(12m/s)^2 - 1/2*1000kg/m^3*12^2/16
= 9.75x10^4Pa = 9.8x10^4Pa
According to CollegeBoard.org:
<u>Answer</u>: "To estimate the probability of observing a value as extreme as pˆ given p."
<u>Explanation</u>: "The test statistic for a one-sample z-test is the distance, in units of standard deviations, between the statistic and the given parameter. From that distance, probabilities (a p-value) can be calculated and a claim can be assessed."
Answer:
1) N = 2. 2) -7/3
Step-by-step explanation:
1)
6 = 3n
6/3 = n
2 = n
n = 2
2)
-3 = 3t + 4
3t + 4 = -3
3t = -3 - 4
3t = -7
T = -7/3
