To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
Sub in 4 as x
3(4) - 29
= -17
Answer:
Step-by-step explanation:
Step 1: Sum of angles on a straight line is 180
Step 2:
2x + 25 + y = 180
2x + y = 180 - 25
2x + y = 155 (1)
Step 3:
3x - 10 + y = 180
3x + y = 180 + 10
3x + y = 190 (2)
Step 4: Substract equation 1 from 2
3x + y - 2x - y = 190 - 155
x = 35
Step 5:
Substitute x in equation 1 to find y
2x + y = 55
2(35) + y = 155
70 + y = 155
y = 155 - 70
y = 85
Answer:
D
Step-by-step explanation:
Because I know
Answer:
v = 8
Step-by-step explanation:
-10= -5/4v first multiply both sides of the equation by -4/5
-10(-4/5) = v this cancels out the right side.
multiply the left side.
so you are left with 40/5 = v
next, simplify you will get 8=v
