<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2</span>
Answer:
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Step-by-step explanation:
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Answer: THE ANSER IS A. No, the domain value 5 corresponds to two range values, -8 and 5.
Find the domain and range.
Domain:
{
6
, 5 ,
1
}
Range:
{
−
7
, −
8 ,
4 ,
5
}
Step-by-step explanation: IT'S NOT C OR D
Determine if the relation is a function.
The relation is not a function.
Answer:
Quadrant 4
there are four quantdrants, A is on the fourth one
See the attached picture:
