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spayn [35]
3 years ago
7

The length of a rectangular frame is 15 inches, and the width of the frame is 88 inches. What is the length of a diagonal of thi

s frame in inches?​
Mathematics
1 answer:
qaws [65]3 years ago
5 0

Answer:

about 89.27 inches

Step-by-step explanation:

This is a right triangle question

c^2 = a^2 + b^2

c^2 = 15^2 + 88^2

c^2 = 225 + 7744

c^2 = 7969

Take the square root of both sides

c = 89.2692556259

c ≈ 89.27 inches

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Misha Larkins [42]
The segment bisector of line JK would be L since it passes through M
How to find JM is that you would have to solve 3x+15=8x+25 to get x and once you find x you just plug it into the equation for JM, 3x+15
3x+15=8x+25 (subtract 8x on both sides)
-5x+15=25 (subtract 15 on both sides)
-5x=10 (Divide on both sides)
x=-2
Plug that in:
3(-2)+15
-6+15
JM=9
8 0
3 years ago
Which answer is it? I just learned this today, so I'm confused.​
Naily [24]

Answer:

H. \sqrt{32} = 5.7 inches

Step-by-step explanation:

1) Because you multiply the length and the width to get the area, you just need to find the square root of the area.

When you look for the square root of 32, it is 5.6....

Round up and you get 5.7 inches which s the length of one side.

Therefore, H. is the correct answer.

4 0
2 years ago
Which statement is true about the potential
dezoksy [38]

Answer:

Only x=-2 is an extraneous solution is the answer

Step-by-step explanation:

3 0
3 years ago
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Evgen [1.6K]
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$45+$60+$7= $112.
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