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mezya [45]
3 years ago
5

An integer is chosen at random from the first 40 positive integers. What is the probability that the integer chosen is divisible

by 6 or 8?
Mathematics
1 answer:
Papessa [141]3 years ago
8 0

Answer:

  1/4

Step-by-step explanation:

There are floor(40/6) = 6 integers in the range that are divisible by 6.

There are floor(40/8) = 5) integers in the range that are divisible by 8.

One of those, 24, is divisible by both 6 and 8, so is counted twice. Then the number of unique numbers 1 to 40 that are divisible by 6 or 8 is ...

 6 + 5 - 1 = 10

The probability of selecting one of those at random is ...

  10/40 = 1/4

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Find 6.3x10^-5/9x10^-3 in scientific notation.
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Answer:

-7 × 10

Step-by-step explanation:

Explanation:

6.3

×

10

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is the same value as

63

×

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4

So we have:

63

×

10

4

9

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3

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ddd

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ddddddddd.d

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If the sum of the digits is exactly divisible by 3 then the actual number is also exactly divisible by 3

→

6

+

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=

9

so we will divide both top and bottom by 3 to simplify the fraction.

ddddddddd.d

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÷

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9

÷

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Note that:

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÷

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21

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1

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so we have:

(

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÷

(

9

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)

=

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Negative version works the same exact way but with a negative sign

6 0
3 years ago
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What’s the answer to this problem?
Alja [10]

Answer:

Figure:         Amount of tiles:

1                    5

2                   8

3                   11

4                   14

5                   17

6                   20

7                   23

8                   26

9                   29

10                 32

11                  35

12                 38

13                 41

The sequence/pattern is +3 tiles.

So Figure 13 will have 41 tiles.

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
3 0
3 years ago
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The tape diagram represents an equation.
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