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4 years ago

NEED HELP ASAP algebra 2

Mathematics

2 answers:

Marina CMI [18]4 years ago

7 0

Answer:

b = sqrt(39)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2+b^2 = c^2

5^2 + b^2 = 8^2

25+b^2 =64

b^2 =64-25

b^2 =39

Take the square root of each side

b = sqrt(39)

MakcuM [25]4 years ago

5 0

Answer:

$\sqrt{39}$

Step-by-step explanation:

Step 1: Find the unknown wide using Pythagorean Theorem

$a^{2}+ b^{2} = c^{2}$

$a^{2}+ 5^{2} = 8^{2}$

$a^{2}+ 25 = 64$

$a^{2}= 64-25$

$a^{2=39$

$\sqrt{a^{2}} = \sqrt{39}$

$a=\sqrt{39}$

$\sqrt{39}$ cannot be simplified and more

Therefore the unknown side is $\sqrt{39}$

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Using long division to find the quotient, what changes do you first

lora16 [44]

Answer:

$\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4$

Step-by-step explanation:

Given

$Dividend = 125x^3 - 8$

$Divisor = 5x - 2$

Required

Determine the quotient

See attachment for complete process.

First, divide 125x^3 by 5x

$\frac{125x^3}{5x} =25x^2$

Write $25x^2$ at the top

Multiply $5x - 2$ by $25x^2$

$= 125x^3 - 50x^2$

Subtract from 125x^3 - 8

i.e.

$125x^3 - 8 - (125x^3 - 50x^2) = 50x^2 - 8$

Step 2:

Divide 50x^2 by 5x

$\frac{50x^2}{5x} = 10x$

Write $10x$ at the top

Multiply $5x - 2$ by $10x$

$= 50x^2 - 20x$

Subtract from 50x^2 - 8

i.e.

$50x^2 - 8 - (50x^2 - 20x) = 20x - 8$

Step 3:

Divide 20x by 5x

$\frac{20x}{5x} = 4$

Write $4$ at the top

Multiply $5x - 2$ by $4$

$= 20x - 8$

Subtract from 20x - 8

i.e.

$20x - 8 - (20x - 8) = 0$

Hence:

$\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4$

8 0

3 years ago

Given the graph of a function f. Identify the function by name. Then Graph, state domain & range in set notation:A) f(x) +2B

WARRIOR [948]

The function in the graph has the name of square function.

The domain of a function is all values of x the function can have. The domain of this function is all real numbers:

$\mleft\lbrace x\in\R\mright\rbrace$

The range of a function is all values of y the function can have. The range of this function is all positive numbers, including zero:

$\mleft\lbrace y\in\R\mright|y\ge0\}$

In order to graph f(x) + 2, we just need to translate the graph 2 units up. To find the new points, we need to increase all y-coordinates by 2:

(-2, 6), (-1, 3), (0, 2), (1, 3), (2, 6)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ 2}

Then, in order to graph f(x) - 2, we just need to translate the graph 2 units down. To find the new points, we need to decrease all y-coordinates by 2:

(-2, 2), (-1, -1), (0, -2), (1, -1), (2, 2)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ -2}

4 0

1 year ago

Please help with this simple trig problem- angle of two sectors of a circle

igomit [66]

Answer:

K = (1/2)r^2(sin(θ) +θ)

Step-by-step explanation:

The area of the triangle to the left is ...

A1 = (1/2)r^2·sin(180°-θ) = (1/2)r^2·sin(θ)

The area of the sector to the right is ...

A2 = (1/2)r^2θ

so the total area of the blue shaded region is ...

K = A1 + A2 = (1/2)r^2·sin(θ) + (1/2)r^2·θ

K = (1/2)r^2(sin(θ) +θ)

4 0

3 years ago

What is 20 increased 30%.

Reptile [31]

When 20 is increased by 30% of itself

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20 + (30% x 20)

20 + (0.3 x 20)

20 + (6)

26

5 0

3 years ago

Need help with this question regarding functions. :)

Tanzania [10]

The Y-intercept is found when X is equal to 0.

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On the graph, when X is 0 the line crosses at Y = 1.

This means that they are equal.

The answer would be equal to.

4 0

4 years ago

NEED HELP ASAP algebra 2​

NEED HELP ASAP algebra 2