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GuDViN [60]
3 years ago
9

What is 4x-3(x-2y) +(6x-8y) in standard form

Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0
7x-2y hope this helps
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Please help fast!!!! Find the seventh term of the geometric sequence if a1=7 and r=3
statuscvo [17]

Answer:

15309 Im pretty sure

Step-by-step explanation:

a7=ar^7

=7(3^7)

7 x 2187=15309

6 0
2 years ago
Which is an equation of the line that passes through (–1, –5) and (–3, –7)
mestny [16]

Answer: y=x-4

Step-by-step explanation: The y value is exactly x minus four.

4 0
3 years ago
A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra
Harman [31]

Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

<em />cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

Step-by-step explanation:

Given

P\ (a,b)

r = \± \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

r = \sqrt{(a)^2 + (b)^2}

Since a belongs to the x axis and b belongs to the y axis;

cos\theta is calculated as thus

cos\theta = \frac{a}{r}

Substitute r = \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}

cos\theta = \frac{a}{\sqrt{a^2 + b^2}}

Rationalize the denominator

cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}

cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

3 0
3 years ago
Can someone help please asap
ch4aika [34]

Sn = (a1) x (1 - r^n) / (1 - r)


Substituting the known values:


S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27 = 8 24/27 = 8 8/9


3 0
3 years ago
Please help me. i don't remember how to do this stuff so please explain it.
AVprozaik [17]

Answer:

which class are you read in?

actually don't know ans

Step-by-step explanation:

hope it's helpful to you

gud nyt

sweet dreams

8 0
3 years ago
Read 2 more answers
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