Answer:
y = 4x - 19
Step-by-step explanation:
The line is parallel to the line whose equation is;
y = 4x + 1
Parallel lines have the same slope so the slope of our line is 4.
The line passes through point (5,1)
Slope = change in y ÷ change in x
Taking another point (x,y) on the line,
Slope = 
= 4
y - 1 = 4x - 20
y = 4x - 19
A=22/10
A=integral(a,b) [f(x)-g(x)]dx
Since the function is even (the function is mirrored over the y axis) we can evaluate the integral from 0 to 1 and then multiply our answer by 2 since we have the same area on each side of the y axis.
We get A=2*int.(0, 1)[(x^2)-(-2x^4)]dx
Now we can integrate by term.
2*[int.(0, 1)[x^2]dx+int(0, 1)[2x^4]dx]
Now factor out constants.
2*[int(0,1)[x^2]dx+2int(0,1)[x^4]dx]
Now integrate.
2*[(x^3/3)|(0,1) + 2*(x^5/5)|(0,1)]
Now solve.
2*[(1/3)+2*(1/5)]
=22/10
Hope you can decipher what I wrote!
Answer:
C: Finance Charge
Step-by-step explanation:
Slope-intercept form:
y=mx+b
m=slope
b=y-intercept
Data of the first line:
m=-5
b=y-intercept=3 (y-intercept=it is the value of "y" when x=0)
y=-5x+3
A line perpendicular to the line y=mx+b will have the following slope:
m`=-1/m
Therefore: the line perpendicular to the line y=-5x+3 will have the following slope:
m´=-1/(-5)=1/5
Point-slope form of a line: we need a point (x₀,y₀) and the slope (m):
y-y₀=m(x-x₀)
We know, the slope (m=1/5) and we have a point (3,2) therefore:
y-y₀=m(x-x₀)
y-2=1/5(x-3) (point-slope form)
y-2=(1/5)x-3/5
y=(1/5)x-3/5+2
y=(1/5)x+7/5 (slope-intercept form)
Answer: the line perpendicular to the first line will be: y=(1/5)x+7/5
J = (5,6)
K = (5,1)
L = (10,2)
