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vaieri [72.5K]
4 years ago
11

Please help lol it’s my hwwwwwwwww

Mathematics
1 answer:
andrezito [222]4 years ago
7 0

Answer:

8/27  is the solution and the alternative form is 0.296 or 2/3 to the power of 3

You might be interested in
In the system shown below, what are the coordinates of the solution that lies in quadrant I?
Arisa [49]

Answer:

(4,3)

Step-by-step explanation:

Given

x^2+y^2=25

x-y^2=-5

In order to solve the equations, from equation 2 we get

-y^2= -5-x

y^2=5+x

Putting the value of y^2 in equation 1

x^2+5+x=25

x^2+5-25+x=0

x^2+x-20=0

x^2+5x-4x-20= 0

x(x+5)-4(x+5)=0

(x+5)(x-4)=0

So

x+5=0  x-4=0

x=-5   x=4

Now for x=-5

x^2+y^2=25

(-5)^2+y^2=25

25+y^2=25

y^2=25-25

y^2=0

so Y=0  

And for x = 4

x^2+y^2=25

(4)^2+y^2=25

16+y^2=25

y^2=25-16

y^2=9

y= ±3

So the solution to the system of equations is

(-5,0) , (4,3), (4,-3)

The only solution that belongs to first quadrant is (4,3)

4 0
3 years ago
Read 2 more answers
Want points answer me question
WITCHER [35]

Answer:

$110

Step-by-step explanation:

1. The total cost:

<em>(3 * 65) + (2 * 70) + (1 * 55)</em> -> cost of dresses + jeans + earrings

Total: 195 + 140 + 55 = <em>390</em>.

2. Money leftover:

<em>500 - 390</em> = $110.

4 0
3 years ago
What is the value of x?<br><br><br> Pls hurry!!!
eduard

Answer:

C. 120

Step-by-step explanation:

Hope it helps!

4 0
3 years ago
Geometry question for homework.
mars1129 [50]

So remember that the distance formula is \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} .

1.

\sqrt{(4-4)^2+(-2-(-5))^2}\\ \sqrt{0^2+3^2}\\ \sqrt{0+9}\\ \sqrt{9}\\ 3

Distance between (4,-5) and (4,-2) is 3 units.

2.

\sqrt{(1-(-1))^2+(1-4)^2}\\ \sqrt{2^2+(-3)^2}\\ \sqrt{4+9}\\ \sqrt{13}

Distance between (1,1) and (-1,4) is √13 (or 3.61 rounded to the hundreths) units.

3 0
3 years ago
Math help please !!!
Varvara68 [4.7K]
Whats the problem ur having in high school youngin
4 0
3 years ago
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