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Katen [24]
3 years ago
15

Which graph represents the function f(x) = 1/3|x|?

Mathematics
2 answers:
slavikrds [6]3 years ago
7 0

Answer:

The correct option is 4.

Step-by-step explanation:

The given function is,

f(x)=\frac{1}{3}|x|

It is a modulus function and its parent function is,

g(x)=|x|

In a function,

f(x)=k|x|

If k>1, then the graph of g(x) stretch vertically and if k<1 then the graph of g(x) compressed vertically.

Since k is \frac{1}{3}, therefore the shoes the vertical compression.

put x=0 in the given function.

f(0)=\frac{1}{3}|0|=0

Put x=3.

f(3)=\frac{1}{3}|3|=1

Therefore the graph passing through (0,0) and (3,1).

Thus fourth option is correct.

Gnom [1K]3 years ago
3 0
Seeing from the graph I've provided above, the correct answer would be D, the last one.

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A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0
2 years ago
Solve for x <br>x/4 ≥ -8<br>a) x≤-2<br>b)x≥-32<br>c)x≥-2<br>d)x≤-32​
Marianna [84]

Answer:

B

Just multiply by 4 to isolate x; because 4 isn't negative, u keep the sign the same.

4 0
3 years ago
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