There is only 1
(x + 3)^3 + 10 = 0
(x + 3)^3 = - 10
(x + 3) = cuberoot(-10)
x = -3 + cuberoot(-10)
There are 50 different possible debating teams that could be selected as obtained using COMBINATION.
Since there are EQUAL number of juniors and seniors ;
Then we have 5 of each.
Here, the order of arrangement DOES NOT matter, Hence, we use COMBINATION
since the team MUST contain 4 SENIORS and 2 JUNIORS
4 Seniors from 5 = 5C4 = 5
2 Juniors from 5 = 5C2 = 10
Hence, (5C4 * 5C2) = 5 * 10 = 50
Hence, there are 50 different possible debating teams that could be selected.
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brainly.com/question/8018593
Answer:
2 - 1+5=6
Step-by-step explanation:
Answer:
So when you flip the coin 8 times and you get tails 3 of the times then you should do 3 plus 5 and you will get 8 as your total again so then the answer is 5 out of 8 total.
Step-by-step explanation:
