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sweet [91]
3 years ago
6

Which represents the solution set to the inequality -1.5(4x + 1) > 4.5 -2.5(x + 1)?

Mathematics
1 answer:
mafiozo [28]3 years ago
6 0

Answer:

(-∞,-1]

Step-by-step explanation:

Got It Right In Edgenuity

You might be interested in
A. Change the following fractions to mixed numbers.
qaws [65]

Answer:

A )

1 - 1\frac{4}{7}

2 - 5\frac{3}{5}

3 - 3\frac{1}{5}

4 - 4\frac{1}{4}

5 - 6\frac{3}{4}

B )

1 - \frac{1}{4}

2 - \frac{2}{3}

3 - \frac{1}{3}

4 - \frac{4}{25}

5 - \frac{5}{8}

C )

1 - 1

2 - \frac{3}{4}

3 - 1

4 - \frac{3}{4}

5 - \frac{7}{9}

D )

1 - \frac{5}{12}

2 - \frac{2}{3}

3 - \frac{1}{3}

4 - \frac{1}{2}

5 - \frac{5}{12}

6 0
3 years ago
Dado el triángulo de vértices en A(-10, -13); B(-2,3) y C(2,1); Hallar la longitud de la perpendicular bajada desde el vértice B
anygoal [31]

Answer:

ghjhjhk

Step-by-step explanation:

4 0
3 years ago
Of the 13 people who have taken their seats at a seminar, 5 have red hair. What is the experimental probability that the next pe
trapecia [35]

Answer:

5/13

Step-by-step explanation:

P(red) =  

red

total

=  

5

13

7 0
3 years ago
Read 2 more answers
Transform x2 + 6x + 8 = 0 into the form (x − p)2 = q?
liraira [26]
So hmmm x²+6x+8=0

alrite.. let's do some grouping now
( x² + 6x + [?]²) + 8 = 0

notice above, we have a missing fellow in order to get a perfect square trinomial... hmm who would that be?

let's take a peek at the middle guy of the trinomial.. 6x.. hmmm let's factor it, 2*3*x, wait a minute!  2 * 3 * x... we already have x² on the left-side, since the middle term is just 2 * the square root of the other two terms, that means that the guy on the right, our missing guy must be "3"

alrite, let's add 3² then, however, bear in mind that, all we're doing is borrowing from our very good friend Mr Zero, 0

so if we add 3², we also have to subtract 3², let's do so

(x² + 6x +3² - 3²) + 8 = 0

(x² + 6x +3²) + 8 - 3² = 0

(x+3)²=3² - 8

(x+3)² = 1
5 0
4 years ago
Read 2 more answers
For ΔABC, ∠A = x + 30, ∠B = 2x - 4, and ∠C = 4x. If ΔABC undergoes a dilation by a scale factor of 1 2 to create ΔA'B'C' with ∠A
Marina86 [1]
ABC
Solve for x
x + 30 + 2x - 4 + 4x = 180 All triangles have 180°. collect like terms.
7x + 26 = 180 subtract 26 to both sides.
7x = 154 Divide by 7
x = 154/7
x = 22
A = x + 30 = 22 + 30 = 52
B = 2x - 4 = 2(22) + 30 = 44 - 4 = 40
C = 4x = 4*22 = 88

Check
<A + <B + <C = 180
<52 + <40 + <88 = 180°
180 = 180

It checks and we are done with this triangle.

A'B'C' 
2x + 8 + x + 18 + 5x - 22 = 180 Collect the like terms.
8x + 4 = 180 Subtract 4 from both sides.
8x = 180 - 4
8x = 176 Divide by 8
x = 176 / 8
x = 22
 
A' = 2x + 8
A' = 2(22) + 8 = 44 + 8 = 52
B' = x + 18 = 22 + 18 = 40
C' = 5x - 22 = 5*22 - 22 = 110 - 22 = 88

Conclusion
A = A'
B = B'
C = C'

All three angles of one triangle are equal to all three angles of the other. So by AA the two triangles are similar.

Comment
Note: the dilation of 12 has nothing to do with this answer. If you were asked about similarity of sides then the 12 would be something to do with the problem. 


3 0
4 years ago
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