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Vedmedyk [2.9K]

2 years ago

15

Dado el triángulo de vértices en A(-10, -13); B(-2,3) y C(2,1); Hallar la longitud de la perpendicular bajada desde el vértice B

a la mediana trazada desde el vértice C.

1 answer:

anygoal [31]2 years ago

4 0

Answer:

ghjhjhk

Step-by-step explanation:

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What is the LCD of 3/16 and 11/24

FrozenT [24]

48 is the lowest denominator

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3 years ago

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Show me subtraction fractions with unlike denominator 5 grad super teacher work sheets

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1/3-1/5

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3 years ago

Our schools swimming pool is 25 meters long. If our coach wants us to swim 3 kilometers, how many lengths of the pool will we ne

liubo4ka [24]

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7 0

3 years ago

What are the next three terms of this sequence? (see picture)

LenKa [72]

Answer:

3, 12, 27,48, 75, 108, 147

Step-by-step explanation:

12-3 = 9

27-12 = 15 (9+6)

48-27 = 21 (15+6)

75-48 = 27 (21+6)

108-75 = 33 (27+6)

147-108 = 39 (33+6)

6 0

3 years ago

how many terms do you have to compute in order for your approximation (your partial sum) to be within 0.0000001 from the converg

Solnce55 [7]

Answer:

The answer is "4 terms".

Step-by-step explanation:

$\sum_{n=1}^{\infty} \frac{(-1)^{n+2} (0.4)^{2n+1}}{(2n+1)!} \ \ \ \ \ error \leq 0.0000001\\\\\\\sum_{n=1}^{\infty} \frac{(-1)^{n+2} (0.4)^{2n+1}}{(2n+1)!} = \frac{-1^{0+2}}{1!}(0.4) + \frac{-1^{1+2}}{3!}(0.4)^3 +\frac{-1^{2+2}}{5!}(0.4)^5+\frac{-1^{3+2}}{7!}(0.4)^7+..\\\\$

$=0.4 - \frac{0.4^3}{3!} + \frac{0.4^5}{5!} - \frac{0.4^7}{7!}+ \frac{0.4^9}{9!} - \frac{0.4^{11}}{11!}+............\\$

Note that, alternatively, positive and negative terms are given in the sequence. It is also alternating

Apply alternative test series:

$\sum_{n=1}^{\infty} (-1)^{n-1} b_n = b_1-b_2+b_3-b_4+b_5-......+(-1)^{n-1} b_n >0\\\\i) b_{n+1}$

use alternating test method we get:

$\sum_{n=1}^{\infty} \frac{-1^{n-1}}{n^2}\\\\s =0.4 - \frac{0.4^3}{3!} + \frac{0.4^5}{5!} - \frac{0.4^7}{7!}+ \frac{0.4^9}{9!} - \frac{0.4^{11}}{11!}+..\\\\b_5= \frac{0.4^9}{9!} = 0.00000000072 < \frac{1}{10^7} =0.0000001$

that's why its value is 4 terms

4 0

3 years ago