This is an equation in STANDARD form for a circle:
(x-h)^2 + (y-k)^2 = r^2
The values of (h, k) are the center point of the circle. When they are put into an equation, their symbols flip as in, if they are positive on a graph, they become negative in the equation and vice versa.
The value (r) is the radius and is squared in the equation. In this case, the square root of 1 is 1.
(x)^2 + (y-6)^2 = 1
Answer:
First statement is wrong
Step-by-step explanation:
Forgive me if I am wrong
Answer:
25
Step-by-step explanation:
Given the indicinal equation
5^-1/5^-3
According to one of the law of indices, if a, b, m and n are integers then;
a^m/a^n = a^(m-n)
When the base are equal, the powers will be subtracted.
Applying this formula to the given expression
5^-1/5^-3
= 5^{-1-(-3)}
= 5^(-1+3)
= 5^2
= 25
Therefore the answer is 25
Answer:
dkjskjsfjkdjkjksjkkjkjdzkj jki don't know sorry something is wrong with my computer
Step-by-step explanation:
