1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Verizon [17]
3 years ago
10

The density of pure solid copper is 8.94 g/mL. What volume does 5 kg of copper occupy. Please help

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0


<u><em>Density= Mass divided by Volume</em></u>, but you're trying to find Volume so you apply Algebra and get <u><em>Volume= Mass divided by Volume.</em></u>

Volume= 0.5592841163 [kg/m (power to the 3)]

You should round it up

You might be interested in
Can the remainder be greater than the quotient?
Helga [31]

Yes and no it depends

but it is possible

4 0
2 years ago
Read 2 more answers
The graph of f(x) = 2x + 4 shifts five units to the right when it is replaced with the graph of f(x) = 2x - k. What is the value
DIA [1.3K]
<h2>Answer</h2>

C.) 1

<h2>Explanation </h2>

Remember the rules for shifting functions:

f(x)+b shifts the function b units upward

f(x)-b shifts the function b units downward

f(x+b) shifts the function b units to the left

f(x-b) shifts the function b units to the right

Since we want tho shift f(x)=2^{x+4} 5 units to the right, we are using the rule: f(x-b) shifts the function b units to the right; in other words, we need to subtract 5 units to the input of the function:

f(x)=2^{x+4-5}

f(x)=2^{x-1}

But notice that there is already a negative sign in f(x)=2^{x-k}, so to get f(x)=2^{x-1}, k must be equal to positive 1.

7 0
2 years ago
Read 2 more answers
I have 30 ones, 82 thousands, 4 hundred thousands, 60 tens, and 100 hundreds. What number am I?
stich3 [128]
This problem tackles the place values of numbers. From the rightmost end of the number to the leftmost side, these place values are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, one hundred millions, and so on and so forth. My idea for the solution of this problem is to add up all like multiples. In this problem, there are 5 multiples expressed in ones, thousands, hundred thousands, tens and hundreds. Hence, you will add up 5 like terms. The solution is as follows

30(1) + 82(1,000) + 4(100,000) + 60(10) + 100(100)

The total answer is 492,630. Therefore, the number's identity is 492,630.
7 0
3 years ago
1) Explain the Distributive Property in your own words.
kenny6666 [7]

Answer:

The Distributive Property states that when a number in parentheses is next to a number, you distribute the number outside of the parentheses and multiply by each of the numbers in parentheses.

5(10+x)=5(10)+5(x)=50+5x

:)

6 0
3 years ago
Can you guys help me? please
mel-nik [20]

Answer:

3 square root 2.

Step-by-step explanation:

I think the answer is b (3 square root 2). the Pythagorean therom states that B^2+ B^2= C^2. we know that c squared is 36. 3 square root 2 is approximately 4.24. ( this squared is 17.98). 17.98 + 17.98 = 35.96.  If i round this up, it is 36.

8 0
3 years ago
Other questions:
  • What is the answer to 3x(2x+1)
    5·1 answer
  • Let v1=(-6,4) and v2=(-3,6) compute the following.
    7·1 answer
  • My question is type an equation for the following pattern.
    13·1 answer
  • Find the area of a triangle with a base of 18 in. and a height of 6 in. Use the formula for area of a triangle
    8·2 answers
  • 29 yd 2ft 11 in + 55 yd 1 ft 10in + 13 yd 1ft 3in=
    15·1 answer
  • There are an infinite number of points that lie on a period at the end of a sentence. True or False?
    10·2 answers
  • There are 3 black marbles and 4 red marbles in a bag.
    7·1 answer
  • Help with this I literally found the answer on chegg but it cost money smh.
    10·1 answer
  • A cuanto le tienes que sumar a 67222 para que llegue a 72622?
    15·2 answers
  • If anyone can help me to solve this.​
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!