Answer:
2/5 (rise over run)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the no of cars be x and no of buses be y.
x + y = 60 -> y = 60 - x
6x + 30y = 600
with the available equations let us calculate the values of x and y.
6x + 30 * (60-x) = 600
6x + 1800 - 30x = 600
24x = 1200
x cars = 50
y buses = 10
maximum profit = 50 * 2.5 + 10 * 7.5 = $200
See attachment although I gather this is not your question. I did the graph(s) for the function,
28! Multiply the 4 rows by the 6 computers per row to get 24 computers, then add the 4 computers in the fifth row to get 28 computers.
