Answer:
18) Area= 5*5/2=25/2=12.5 unit ^2
19) Area=AB^2V3/4=8a^2*V3/4=2V3a^2
Step-by-step explanation:
18. A(-3,0)
B(1,-3)
C(4,1)
AB=V(-3-1)^2+(0+3)^2=V16+9=V25=5
AC=V(-3-4)^2+(0-1)^2=V49+1=V50=5V2
BC=V(1-4)^2+(-3-1)^2=V9+16=V25=5
so AB=BC=5
and AC^2=AB^2+BC^2
so trg ABC is an isosceles right angle triangle (<B=90)
Area= 5*5/2=25/2=12.5 unit ^2
19. A(a,a)
B(-a,-a)
C(-V3a, V3a)
AB=V(a+a)^2+(a+a)^2=V4a^2+4a^2=V8a^2
AC=V(a+V3a)^2+(a-V3)^2=Va^2+2a^2V3+3a^2+a^2-2a^2V3+3a^2=V8a^2
BC=V(-a+V3a)^2+(-a-V3a)^2=V8a^2
so AB=AC=BC
Area=AB^2V3/4=8a^2*V3/4=2V3a^2
Answer: Jack
Step-by-step explanation: This is because you already found out the 78% so therfore you have to find the decimals and then convert it to a percentage. the fraction (jack) converts to .875 which is 87.5%. Then the decimal is 73%.
Answer:
Step-by-step explanation:
In this equation what is strange is probably using the letter a as the unknown, but this is a matter of choice we could have calle y or z for that matter. Then we will treat it ans any other equation and solve it.
-11 -5a = 6(5a+4)
-11 -5a= 30a + 24
-11 - 24 = 30a + 5a (placing the unknown a in the rght side and the numbers in the left to solve the equation)
- 35 = 35a
-35/35 = a
- 1= a
Your answer be c/3
because it shows you 27 student
but it shows 2/3 of the students wearing sneakers
did this answer help
1) 18h = 252
You divide each side by 18, so you can get "h" alone on a side, and its value on the other side of the equation.
(18h)/18 = 252/18
h = 14 (Answer C)
2) 31d = 186.
Same Thing, you divide each side by 31, so you can get "d" alone on a side, and its value on the other side of the equation.
(31d)/31 = 186/31
d= 6 (Answer B)
3) 55c = 385
Again, same thing, You divide each side by 55, so you can get "c" alone on a side, and its value on the other side of the equation.
(55c)/55 = 385/55
c = 7 (Answer B)
4) 50w = 1050
You divide each side by 50, so you can get "w" alone on a side, and its value on the other side of the equation.
(50w)/50 = 1050/50
w=21 (Answer A)
As you can notice, they all follow the same steps: dividing by the coefficient of the variable both sides, so you can the variable alone on the first side of the equation, and its value on the second side.
Hope this Helps! :)
