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3 years ago

How will you convert a decimal fraction into its hexadecimal form by a process Of

Computers and Technology

2 answers:

elena-14-01-66 [18.8K]3 years ago

7 0

To make a fraction a decimal you have to divide the denominator and the numerator

Juliette [100K]3 years ago

7 0

Answer:

To convert a decimal fraction into hexadecimal form follow this steps:

Divide the decimal number by 16
multiply the remainder i.e the number that appears after the decimal point of the result you got from step 1 by 16
repeat the process until you get a decimal result of 0
the hexadecimal form will be the results gotten from step 2 starting from bottom to the top.

Explanation:

Example: convert 2210 decimal to hexadecimal

step 1 :

2210 / 16 = 138.125 this means that the new decimal will be 138 and the remainder is 0.125

step 2 :

multiply .125 by 16 = 2

repeat step 1:

138 / 16 = 8.625 this means the new decimal is 8 and the remainder is 0.625

repeat step 2:

multiply .625 by 16 = 10

Repeat step 1 and step 2 until the new decimal becomes 0 then you can stop and then write out your result from steps 2 from bottom upwards to get the hexadecimal equivalent of 2210 decimal.

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2 years ago

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3 years ago

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3 years ago

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Write a c program that reprints input so that no line is longer than 50 characters. Specifically, for lines less than or equal t

Alex73 [517]

Using the knowledge in computational language in C++ it is possible to write a code that reprints prints input so that no line is longer than 50 characters.

<h3>Writting the code:</h3>

#include<stdio.h>

int main(int argc, char** argv){

//creating pointer to read a file

FILE * fp;

char * line = NULL;

size_t len = 0;

ssize_t read;

int i=0;

//opening a file

fp = fopen(argv[1], "r");

//handling the error condition

if (fp == NULL){

printf("File not found..!!");

return 0;

}

int moreThan50 =0;

//reading a file line by line

while ((read = getline(&line, &len, fp)) != -1) {

i = 0;

if(read >= 50){

moreThan50++;

}

while(i < read){

if(line[i]!='\n'){

if(i%50 == 0){

printf("\n%c",line[i]);

}else{

printf("%c",line[i]);

}

i++;

}

printf("\nTotal lines over 50 chars: %d\n",moreThan50);

printf("Offending Lines: ");

for(i=1;i<=moreThan50;i++)

printf("%d, ",i);

fclose(fp);

return 0;

}

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2 years ago

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lukranit [14]

Answer:

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Explanation:

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3 years ago