Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
XLS would be it, avi contains like sounds and stuff
Here are some of the computers used in the first generation of computers:
ENIAC
EDVAC
UNIVAC
IBM-701
IBM-650
These are some of the first computers ever that led to today's computers.
1. ain't, your name, your last name.
2. to ensure a fulfilled document
3. to find what you want then select it
Answer:
Answered below
Explanation:
//Program is written in Java programming //language
Class Box{
private double length;
private double width;
private double height;
Box(double len, double wid, double hgt){
length = len;
width = wid;
height = hgt;
}
public double volumeOfBox( ){
double volume = length * width * height;
return volume;
}
public double getLength( ){
return length;
}
public double getWidth( ){
return width;
}
public double getHeight( ){
return height;
}
}
