3 years ago

PLEASE HELP ME

Mathematics

1 answer:

Inessa [10]3 years ago

6 0

Answer:

( 1 , 1 )

Step-by-step explanation:

y = 3x - 2

1 = 3(1) - 2

1 = 3 - 2

1 = 1

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How do you find the sum of cube ?

SIZIF [17.4K]

Answer:

$(2x+5)(4x^{2} -10x+25)=0$

Step-by-step explanation:

Given:

The given equation is.

$8x^{3} +125=0$

Find the some of cube.

Solution:

$8x^{3} +125=0$

$2^{3}x^{3} +5^{3}=0$

$(2x)^{3} +5^{3}=0$ ----------(1)

The sum of the cube formula is given below.

$(a^{3} +b^{3})=(a+b)(a^{2} -ab+b^{2} )$ -----------(2)

By comparing equation 1 and equation 2

$a=2x, b=5$

substitute a and b value in equation 2

$((2x)^{3} +5^{3})=(2x+5)((2x)^{2} -(2x)(5)+5^{2})$

$((2x)^{3} +5^{3})=(2x+5)(4x^{2} -(10x)+25)$

$((2x)^{3} +5^{3})=(2x+5)(4x^{2} -10x+25)$

Therefore the sum of the cube $(2x+5)(4x^{2} -10x+25)=0$

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