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steposvetlana [31]

3 years ago

5

A runner increases her speed from 3.1 m/s to 3.5 m/s during her last 15 seconds of great run. What was her acceleration during h

er big push to the finish?

1 answer:

docker41 [41]3 years ago

5 0

The runner accelerated her speed by 0.026 m/s during the last 15 seconds of her run.

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Can you help me plz

Gelneren [198K]

i think the answer would be C

4 0

3 years ago

Please finish this equation and write the answer

olga55 [171]

Given:

The equation is:

$2540=\dfrac{22}{7}r^2(20)$

To find:

The solution for the given equation.

Solution:

We have,

$2540=\dfrac{22}{7}r^2(20)$

It can be written as:

$\dfrac{2540\times 7}{22\times 20}=r^2$

$\dfrac{17780}{440}=r^2$

$\dfrac{889}{22}=r^2$

Taking square root on both sides, we get

$\sqrt{\dfrac{889}{22}}=r$ [Radius cannot be negative]

$r=6.3568145$

$r\approx 6.36$

Therefore, the value of r is about 6.36 cm.

7 0

3 years ago

Find the differential of

anyanavicka [17]

$f(x,y)=x^2+y^3\implies \left.\cfrac{}{} 2x+3y^2 \right]_{\stackrel{\textit{\small x=2}}{\textit{\small y=1}}}\implies 2(2)+3(1)^2\implies 7$

8 0

2 years ago

The Area of a rectangle is 3x2 + 9x square inches. The length of the rectangle is 3x inches.

Roman55 [17]

Width of the rectangle is x + 3 in

Step-by-step explanation:

Step 1: Given area of the rectangle = 3x² + 9x in². Length = 3x in. Find width.

Area = length × width

3x² + 9x = 3x × width

∴ Width = 3x² + 9x/3x = x + 3 in

3 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%20980" id="TexFormula1" title="\sqrt{ 980" alt="\sqrt{ 980" align="absmiddle" class

Katarina [22]

31.304951684997 definitely

7 0

3 years ago

Read 2 more answers