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2 years ago

Ellie wants to buy raspberries and kiwi to make a fruit tart. Raspberries cost $4 per

Mathematics

1 answer:

Butoxors [25]2 years ago

4 0

Total pounds of 2.5 pounds of raspberries and 2 pounds of kiwi bought is 4.5 pounds.

Total pounds of 2 pounds of raspberries and y pounds of kiwi is (2 +y) pounds.

In order to determine the total pounds of fruits Ellie buys, the pounds of raspberries bought would be added to the pounds of Kiwi she bought.

Addition is the process of determining the total value of two or more numbers by adding the numbers together. It is one of the basic mathematical operations.

Total pounds Ellie bought when she buys 2.5 pounds of raspberries and 2 pounds of kiwi: 2.5 + 2 = 4.5 pounds.

Total pounds Ellie bought when she buys 2 pounds of raspberries and y pounds of kiwi: 2 + y = (2 +y) pounds.

To learn more about addition, please check: brainly.com/question/349488

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<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 700, \sigma = 50$ .

The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:

X = 790:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{790 - 700}{50}$

Z = 1.8

Z = 1.8 has a p-value of 0.9641.

X = 575:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{575 - 700}{50}$

Z = -2.5

Z = -2.5 has a p-value of 0.0062.

0.9641 - 0.0062 = 0.9579.

0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

More can be learned about the normal distribution at brainly.com/question/4079902

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