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Damm [24]
3 years ago
7

Ellie wants to buy raspberries and kiwi to make a fruit tart. Raspberries cost $4 per

Mathematics
1 answer:
Butoxors [25]3 years ago
4 0

Total pounds of 2.5 pounds of raspberries and 2 pounds of kiwi bought is 4.5 pounds.  

Total pounds of 2 pounds of raspberries and y pounds of kiwi is  (2 +y) pounds.

In order to determine the total pounds of fruits Ellie buys, the pounds of raspberries bought would be added to the pounds of Kiwi she bought.

Addition is the process of determining the total value of two or more numbers by adding the numbers together. It is one of the basic mathematical operations.

Total pounds Ellie bought when she buys 2.5 pounds of raspberries and 2 pounds of kiwi: 2.5 + 2 = 4.5 pounds.

Total pounds Ellie bought when she buys 2 pounds of raspberries and y pounds of kiwi: 2 + y = (2 +y) pounds.

To learn more about addition, please check: brainly.com/question/349488

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The volume of a cylinder can is 1.54 litre and area of base is 77cm^2 Find its height​
goblinko [34]

Answer:

The height is 20 cm.

Step-by-step explanation:

First, we have to know that the volume formula is V = πr²h and the base area of cylinder is a circle. So we can let πr² be 77 cm² . Then we have to substitute the following values into the formula :

v = 1.54 \: l

v = 1540 \:  {cm}^{3}

v = \pi \times  {r}^{2}  \times h

Let πr² be 77,

Let v be 1540,

1540 = 77 \times h

77h = 1540

h = 1540  \div 77

h = 20 \: cm

5 0
3 years ago
Y is directly related to x and y is 81 when x is 27 the constant of.variation is
suter [353]

Answer:

The constant of variation is 3

Step-by-step explanation:

Given.

y=81

x=27

And y is directly related to x

y ∝ x

Here k is constant of variation

y=kx

k=\frac{y}{x}--------------(1)

Put the y and x value in equation 1.

k=\frac{81}{27}

k=3

So, the constant of variation is 3.

6 0
3 years ago
5<br> 2. Simplify<br> .<br> 5<br> O 57<br> O 5-1<br> o<br> 5<br> O<br> 57
pantera1 [17]

Answer:

79853709 with the exponent of 94

Step-by-step explanation:

8 0
3 years ago
Write the equation of the line that passes through the points (4, -6) and (-2,3).
Butoxors [25]
In point slope form, the answer would be y = - 3/2 x it’s one fraction
5 0
3 years ago
Read 2 more answers
In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

\mu_s=np=500*0.90=450

The standard deviation will be:

\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
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