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KengaRu [80]
4 years ago
13

A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(in feet) h(t)=100t-16t sq

uared . What is the maximum height that the ball will reach? Do not round your answer.
Mathematics
1 answer:
guapka [62]4 years ago
4 0
Given the height of the ball at time, t is modeled by:
h(t)=100t-16t^2
the maximum height will be found as follows:
at maximum height:
h'(t)=0
thus given h(t), the derivative will be:
h'(t)=100-32t=0
solving for t we get
t=100/32
thus the time taken for the ball to reach maximum height is t=100/32. Hence the maximum height will be:
h(100/32)=100×100/32-16×(100/32)²
=156.25 ft
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