AREA OF SQUARE = SIDE * SIDE
==> (X-3)*(X-3) = (X-3)² = X²-6X+9 UNITS²
Let x and y represent the smaller and larger numbers, respectively.
y - x = 5 . . . . . the difference is 5
3y = 4x + 6 . . 3 times the larger is 4 times the smaller plus 6
Add x to the first equation to get an expression for y.
y = x + 5
Use that in the second equation.
3(x + 5) = 4x + 6
3x + 15 = 4x + 6 . . . . . eliminate parentheses
9 = x . . . . . . . . . . . . . . add -3x-6
y = x+5 = 14
smaller number: 9
larger number: 14
X^2 + y^2 can be replaced by r^2 to obtain the polar equation equivalent to x^2 + y^2 = 5. Thus, r^2 = 5, and r = sqrt(5). That's all that's necessary. No matter what the angle is, r will always be sqrt(5).
Answer:
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Step-by-step explanation:
<u>The concept:</u>
We are given the equation:
Which can be simplified as:
Since any number to the power '0' is 1
x² - x must be equal to 0 for the given equation to be true
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<u>Solving for x:</u>
x² - x = 0
x(x-1) = 0
now, we can divide both sides by either x OR x-1
So we will see what we get for either choice:
x = 0/(x-1) x-1 = 0/x
x = 0 x = 1
Hence, the value of x is either 0 or 1
