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algol [13]
3 years ago
7

Factor the polynomial. 8x^2 - 50

Mathematics
1 answer:
blsea [12.9K]3 years ago
6 0
2 • (2x + 5) • (2x - 5)
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Solve for C: A= b over c
Nikolay [14]

Answer:

a times b =c

Step-by-step explanation:

3 0
3 years ago
If y is 12 less than the product of a and b, then which of the following is an expression for y in terms of a and b ?
AVprozaik [17]
Answer: ab -12 

Given that y is 12 less than the product of a and b. 

The product of a and b is the multiplication of a and b:
a x b = ab

12 less than the product will mean that we need to take away 12 from ab, so 
y = ab - 12

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Answer: ab - 12
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8 0
4 years ago
Help please ! It’s geometry
Scorpion4ik [409]

Answer:

x = 11 \sqrt{2}

y = 11 \sqrt{2}

Step-by-step explanation:

\sin(45)  =  \frac{y}{22}  \\  \\  \frac{1}{ \sqrt{2} }  =  \frac{y}{22}  \\  \\ y =  \frac{22}{ \sqrt{2} }  \\  \\ y = 11 \sqrt{2}

\cos(45)  =  \frac{x}{22}  \\  \\ x = 11 \sqrt{2}

4 0
3 years ago
Read 2 more answers
What is the solution to the equation -3(h+5)+2 = 4(n+6)-9
elixir [45]

here is your answer. i think i did it right.

6 0
3 years ago
For what values of q are the two vectors A = i + j + kq each other and B-iq-23 + 2kg perpendicular to
Sloan [31]

Answer:

The value of q are 0.781,-1.281.

Step-by-step explanation:

Given : Two vectors A=i+j+kq and B=iq-2j+2kq are perpendicular to each other.

To find : The value of q ?

Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. \vec{A}\cdot \vec{B}=0

Two vectors A=i+j+kq and B=iq-2j+2kq

(i+j+kq)\cdot (iq-2j+2kq)=0

(1)(q)+(1)(-2)+(q)(2q)=0

q-2+2q^2=0

2q^2+q-2=0

2q^2+q-2=0

Using quadratic formula,

q=\frac{-1\pm\sqrt{1^2-4(2)(-2)}}{2(2)}

q=\frac{-1\pm\sqrt{17}}{4}

q=\frac{-1+\sqrt{17}}{4},\frac{-1-\sqrt{17}}{4}

q=0.781,-1.281

Therefore, The value of q are 0.781,-1.281.

6 0
3 years ago
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