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3 years ago

7

Factor the polynomial. 8x^2 - 50

1 answer:

blsea [12.9K]3 years ago

6 0

2 • (2x + 5) • (2x - 5)

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Solve for C: A= b over c

Nikolay [14]

Answer:

a times b =c

Step-by-step explanation:

3 0

3 years ago

If y is 12 less than the product of a and b, then which of the following is an expression for y in terms of a and b ?

AVprozaik [17]

Answer: ab -12

Given that y is 12 less than the product of a and b.

The product of a and b is the multiplication of a and b:
a x b = ab

12 less than the product will mean that we need to take away 12 from ab, so
y = ab - 12

-----------------------------------------------
Answer: ab - 12
-----------------------------------------------

8 0

4 years ago

Help please ! It’s geometry

Scorpion4ik [409]

Answer:

$x = 11 \sqrt{2}$

$y = 11 \sqrt{2}$

Step-by-step explanation:

$\sin(45) = \frac{y}{22} \\ \\ \frac{1}{ \sqrt{2} } = \frac{y}{22} \\ \\ y = \frac{22}{ \sqrt{2} } \\ \\ y = 11 \sqrt{2}$

$\cos(45) = \frac{x}{22} \\ \\ x = 11 \sqrt{2}$

4 0

3 years ago

Read 2 more answers

What is the solution to the equation -3(h+5)+2 = 4(n+6)-9

elixir [45]

here is your answer. i think i did it right.

6 0

3 years ago

For what values of q are the two vectors A = i + j + kq each other and B-iq-23 + 2kg perpendicular to

Sloan [31]

Answer:

The value of q are 0.781,-1.281.

Step-by-step explanation:

Given : Two vectors $A=i+j+kq$ and $B=iq-2j+2kq$ are perpendicular to each other.

To find : The value of q ?

Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. $\vec{A}\cdot \vec{B}=0$

Two vectors $A=i+j+kq$ and $B=iq-2j+2kq$

$(i+j+kq)\cdot (iq-2j+2kq)=0$

$(1)(q)+(1)(-2)+(q)(2q)=0$

$q-2+2q^2=0$

$2q^2+q-2=0$

$2q^2+q-2=0$

Using quadratic formula,

$q=\frac{-1\pm\sqrt{1^2-4(2)(-2)}}{2(2)}$

$q=\frac{-1\pm\sqrt{17}}{4}$

$q=\frac{-1+\sqrt{17}}{4},\frac{-1-\sqrt{17}}{4}$

$q=0.781,-1.281$

Therefore, The value of q are 0.781,-1.281.

6 0

3 years ago