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2 years ago

Please answer for me

Mathematics

1 answer:

solong [7]2 years ago

6 0

It should equal 12.56

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Help with question 17!

solniwko [45]

Do you have to find the angle or the measurement?

8 0

3 years ago

Yousuf buys a pen that cost AED 2.12. How much will 4 such pen cost? GUYS PLEASE QUICK I HAVE AN EXAM RN

charle [14.2K]

Answer:

8.48

Step-by-step explanation:

4 x 2.12 = 8.48 AED

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5 0

2 years ago

Read 2 more answers

What is the value of n in the proportion below n/28 = 4/7

butalik [34]

n is 16

$\frac{n}{28} = \frac{4}{7} \\ n = \frac{4 \times 28}{7} = 16$

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3 0

3 years ago

Read 2 more answers

Make x the subject of the formula y= b/ax

neonofarm [45]

Answer:

x=b/(ay)

Step-by-step explanation:

To make x the subject of the formula, we basically have to isolate the x.

To do this we first multiply both sides by x.

xy=b/a

Now, to isolate the x, we simply divide by y,

x=b/(ay)

So x=b/(ay) is our answer

8 0

3 years ago

The manufacturer of a CD player has found that the revenue R (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com

AleksAgata [21]

Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

$R(p) = -5p^2 + 1550p$

where p is unit price in dollars.

First, we differentiate R(p) with respect to p, to get,

$\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550$

Equating the first derivative to zero, we get,

$\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155$

Again differentiation R(p), with respect to p, we get,

$\dfrac{d^2(R(p))}{dp^2} = -10$

At p = 155

$\dfrac{d^2(R(p))}{dp^2} < 0$

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

$R(155) = -5(155)^2 + 1550(155) = 120125$

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

6 0

3 years ago