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Lelu [443]
3 years ago
8

An underground mine elevator descends 12% of the total depth every minute. The total depth of the elevator is 75 meters below th

e ground. How many meters below the ground is the elevator after 2 minutes? A: -18 meters B: -9 meters C: -4.5 meters D: -22.5 meters
Mathematics
2 answers:
Katarina [22]3 years ago
5 0
75/100 = 0.75

--------------------

12 x 0.75 = 9

* The mine elevator travels a
distance of 9 metres per minute.

---------------------

After 2 minutes, the mine elevator
would've travelled 18 metres,
therefore your answer is:

A: -18 metres
earnstyle [38]3 years ago
3 0

Answer:

A: -18 meters 0w0            

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State if the triangle is congruent
melisa1 [442]

Answer:

Step-by-step explanation:

m∠ JHI + m∠GHJ = 180    { linear pair}

m∠JHI + 90 = 180

m∠JHI = 180 -90 = 90

In ΔGHJ and ΔJHI,

          GJ = IJ   { given}

         JH = JH    {common}

 m∠ JHI = m∠GHJ  { above proved}

ΔGHJ  ≅ ΔJHI     { Angle Side Side congruence}

8 0
2 years ago
The drawing shows a heart-shaped figure. The heart is composed of a square and two semicircles. The semicircles have the center
Dvinal [7]

Answer:

Area = πx² + x² or x²(π + 1)

Step-by-step explanation:

The area of the heart = area of a circle + area of the square

Note:

1. The 2 semicircles makes 1 full circle

2. The diameter of the circle = the side length of the square

Thus:

Area of the heart = πr² + s²

Where,

r = x

s = x

Formula for area of the heart = π(x²) + x² = πx² + x²

Area = x²(π + 1)

4 0
2 years ago
1.2(4x – 1) = 8x – 2
zysi [14]

6x

Step-by-step explanation:

1.2(4x-1)=8x-2=6x

3 0
2 years ago
Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground
Scorpion4ik [409]

Answer:

125.4\ \text{m/s}

Step-by-step explanation:

u = Initial velocity of baseball

\theta = Angle of hit = 30^{\circ}

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

y_0 = Height of hit = 2.5 ft

a_y = g = Acceleration due to gravity = 32.2\ \text{ft/s}^2

t = Time taken

Displacement in x direction

x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}

Displacement in y direction

y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}

The minimum initial velocity needed for the ball to clear the fence is 125.4\ \text{m/s}

5 0
3 years ago
A particle moves along the x-axis so that its velocity in feet per second at time x, in seconds, is modeled by the quadratic fun
Katyanochek1 [597]

For this case we have the following equation:

y = 2x ^ 2 - 10x + 12

Where, we have the following variables:

x: time in seconds

y: speed in feet per seconds

For the initial velocity, we evaluate x = 0 in the given equation:

y = 2 (0) ^ 2 - 10 (0) + 12\\y = 12

Therefore, the initial speed is 12 feet per second.

Answer:

The particle's initially velocity is 12.

6 0
3 years ago
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