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2 years ago

Who want brainliest?

Mathematics

1 answer:

9966 [12]2 years ago

4 0

Answer:

lol me and thanks :p

Step-by-step explanation:

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HELP PLEASE!! Function G is a transformation of the parent exponential function. Which STATEMENTS are true about function g.

seraphim [82]

Answer:

c. function g has A y intercept of (0,4)

8 0

2 years ago

A bed is 2400 a discount of 25% was given on the

Brrunno [24]

Answer:

800

Step-by-step explanation:

Given: The selling price of bed is 2400.

Discount offered is 25%

Lets assume the cost of bed be "x"

Discount offered on the cost price of bed= $\frac{25}{100} \times x= 0.25x$

∴ Discount offered on the cost price of bed= 0.25x

We know the selling price of bed after discount provided.

Finding the cost price of the bed.

⇒ $x-0.25x= 2400$

⇒ $0.75x= 2400$

cross multiplying both side.

∴ $x= \frac{2400}{0.75} = 3200$

∴ Cost price of the bed is 3200.

We know selling price of the bed is 2400.

Now, finding the saving.

Saving on the price of bed= Cost price- selling price

Saving= $3200-2400= 800$

Hence, saving on the purchase of the bed is 800.

7 0

3 years ago

Q12 A driver sees this speed limit sign in France. The speed is in kilometres per hour

olga nikolaevna [1]

Answer:

Step-by-step explanation: idk

7 0

3 years ago

Dustin polled 127 drivers late on a Friday night.

Maslowich

Answer:

yes

Step-by-step explanation:

6 0

3 years ago

Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc

Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when $M = 0.3, \sigma = 4.103$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.3 = 1.96*\frac{4.103}{\sqrt{n}}$

$0.3\sqrt{n} = 1.96*4.103$

$\sqrt{n} = \frac{1.96*4.103}{0.3}$

$(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}$

$n = 718.57$

Rouding up

We need a sample size of at least 719

6 0

2 years ago