Answer:
2,93x10³atmL, 2,97x10⁵J
Explanation:
The work done in gas compression under constant pressure is:
W = -P×ΔV
<em>Where W is work done, P is pressure and </em>ΔV <em>is change in volume (Vol.f - Vol.i)</em>
Replacing:
W = -61.0atm×(51.0L - 99.0L)
W = 2928atmL = <em>2,93x10³atmL</em>
In Joules:
2928atmL × (101,325J / 1atmL) = 296680J ≡<em> 2,97x10⁵J</em>
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I hope it helps!
Answer:
Moles = 8 moles
Solution:
Molarity is given as,
Molarity = Moles / Volume of Solution ------ (1)
Data Given;
Molarity = 2 M
Volume = 4 L
Solving eq.1 for Moles,
Moles = Molarity × Volume of Solution
Putting values,
Moles = 2 mol.L⁻¹ × 4 L
Moles = 8 moles
76.1 gram = 1 mole of CS2
since CS2 contains 2 moles of S
the 76.1 gram of CS2 will contain the 2 mole of S atoms
There are 24 protons in Chromium. You get the number of neutrons by subtracting the number of protons from the mass number which is the total number of protons and neutrons. Chromium's mass number is 52. You would subtract 24 from 52. 52-24=28. There are 28 neutrons in chromium.
1374.75 is the concentration in milligrams per ml of a solution containing 23.5 meq sodium chloride per milliliter.
Concentration in chemistry is calculated by dividing a constituent's abundance by the mixture's total volume.
It is calculated in mg/ml.
The unit of measurement frequently used for electrolytes is the milliequivalent (mEq). This value compares an element's chemical activity, or combining power, to that of 1 mg of hydrogen.
Formula for calculating concentration in mg/ml is
Conc. (mg/ml) = M(eq) /ml × Molecular weight / Valency
Given
M(eq) NaCl/ ml = 23.5
Molecular weight pf NaCl = 58.5 g/mol
Valency = 1
Putting the values into the formula
Conc. (mg/ml) = 23.5 ×58.5/1
= 1374.75 mg/ml
Hence, 1374.75 is the concentration in milligrams per ml of a solution containing 23.5 meq sodium chloride per milliliter.
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