<span>Acid rain is precipitation that contains high levels of nitric or sulfuric acid. Natural and industrial sources can release sulfur dioxide and nitrogen oxide into the atmosphere, leading them to combine chemically with oxygen and water to form their respective acidic molecules. These acids are then deposited through rain or dust depending on the climate of the region. While acid rain can occur anywhere in the world, it is prevalent in regions that have high industrial activity.</span>
Methane is lighter than air, having a specific gravity of 0.554. It is only slightly soluble in water. It burns readily in air, forming carbon dioxide
and water vapour; the flame is pale, slightly luminous, and very hot.
The boiling point of methane is −162 °C (−259.6 °F) and the melting
point is −182.5 °C (−296.5 °F). Methane in general is very stable, but
mixtures of methane and air, with the methane content between 5 and 14
percent by volume, are explosive. Explosions of such mixtures have been
frequent in coal mines and collieries and have been the cause of many
mine disasters.
Answer:
See explanation
Explanation:
In looking at molecules to determine whether they are polar or not we have to look at two things basically;
i) presence of polar bonds
ii) geometry of the molecule
Now, we know that CCI2F2 is a tetrahedral molecule, but the molecule is not symmetrical. It has four polar bonds that are not all the same hence the molecule is polar.
In an electric field, polar molecules orient themselves in such a way that the positive ends of the molecule are being attracted to the negative plate while the negative ends of the molecules are attracted to the positive plate.
So the positive ends of CCI2F2 are oriented towards the negative plate of the field while the negative ends of CCI2F2 are oriented towards the positive ends of the field.
Answer:
[OH⁻] = 0.002 M
Explanation:
<u>The definition of pOH</u> is similar to the definition of pH:
This means that with a <u>given pOH value</u>, the calculation of [OH⁻] is a matter of algebra:
To remove the logarithm we increase 10 by the power of the pOH:
=[OH⁻]
