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Vera_Pavlovna [14]
3 years ago
8

Gilbert's employer matches 12% of Gilbert's contributions to his 401(k) plan. If Gilbert's employer contributed $600 to the plan

last year, how much did Gilbert contribute to the plan last year?
A. $7200
B. $4400
C. $5600
D. $5000
Mathematics
2 answers:
alexira [117]3 years ago
3 0
12% of Gilbert's contribution is 600
0.12x = 600
x = 600/0.12
x = 5000 <==
dem82 [27]3 years ago
3 0

Answer:

D. $5000

Step-by-step explanation:

Let "x" be the Gilbert contribution.

Gilbert's employer contribution is 12% which is $600.

12% of x = 600

12/100 * x = 600

0.12*x =  600

Dividing both sides by 0.12, we get

x = 600/0.12

x = $5000

Answer: D. $5000

Hope this will helpful.

Thank you.

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Alex, Bob, and Cole have a combined weight of 111 kilograms. If Alex weighs 44 kg, and Bob weighs three-forth of Alex's weight,
vlabodo [156]

Answer:34

Step-by-step explanation:

Weight of Alex:44

Weight of Bob:44*(3/4)

=33

Combined weight of all of them:111

Combined weight of Alex and Bob=44+33=77

Cole's weight=111-77 =34

8 0
3 years ago
A recent taste test showed that 85% of people liked a new chicken sandwich recently added to a restaurant’s menu. The restaurant
Vesna [10]

Answer:

a) The margin of error = 0.11

b) The interval estimate = (0.74, 0.96)

c) Not valid because 68% = 0.68 is less than the values in the interval estimate

Step-by-step explanation:

The statistical data from the population and the simulation are;

The percentage of the people that liked the new chicken sandwich = 85% = The population proportion

The percentage the restaurant manager claims liked the new sandwich = 68%

The number of trials of the simulation = 100 trials

The sample size of each trial = 30

The point estimate of each trial = 0.85

The minimum sample proportion = 0.66

The maximum sample proportion = 0.88

a) The confidence interval = (0.66, 0.88)

By the half the range method, the margin of error is given by half the width of the confidence interval

∴ The margin of error, MOE = (0.88 - 0.66)/2 = 0.11

b) The interval estimate are the expected range of numbers for a parameters

The interval estimate = The point estimate ± MOE

∴ The interval estimate = 0.85 ± 0.11 = (0.74, 0.96)

Given that the manager's claim of 68% is not within the interval estimate, the manager's claim is not valid based on the expected values for the people that liked the new sandwich found with the point estimate and the margin of error

3 0
3 years ago
Jill says that 12.6 is less than 12.63. explain her error
kenny6666 [7]

No the both are having first integer same and jolly dosen’t mention the 2nd integer after the decimal that is her error

7 0
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olga nikolaevna [1]

Answer:

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Step-by-step explanation:

.

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Answer: D:

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Step-by-step explanation:

7 0
3 years ago
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