=> 8 = 8 Maybe?
Sorry if this isnt right!
Answer:
I believe the answer would be 57.9
Step-by-step explanation:
You would have to divide 376.35 by 6.5.
Hope this helps :D
Answer:
The 90% confidence interval is (493.1903, 550.2097), and the critical value to construct the confidence interval is 2.0150
Step-by-step explanation:
Let X be the random variable that represents a measurement of helium gas detected in the waste disposal facility. We have observed n = 6 values, 
= 521.7 and S = 31.6368. We will use
as the pivotal quantity. T has a 
distribution with 5 degrees of freedom. Then, as we want a 90% confidence interval for the mean level of helium gas present in the facility, we should find the 5th quantile of the t distribution with 5 degrees of freedom, i.e., 
, this value is -2.0150. Therefore the 90% confidence interval is given by
, i.e.,
(493.1903, 550.2097)
To find the 5th quantile of the t distribution with 5 degrees of freedom, you can use a table from a book or the next instruction in the R statistical programming language
qt(0.05, df = 5)
Distance=speed*time
distance traveled by plane A after 40 minutes:
distance=570×40/60=380 miles
Distance traveled by B after 40 minutes
distance=20/60×585=195 miles
Thus the distance between them will be given using cosine law:
c^2=a^2+b^2-2ab Cos C
thus we shall have:
c^2=380^2+195^2-2*380*195*cos22
c^2=45016.35275
c=212.171 miles
Thus the distance between them after 40 minutes is 212.171 miles
Answer:
depends on the sized of the room-send picture so I can help
Step-by-step explanation:
